A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 241933 Accepted Submission(s): 46646
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The
first line of the input contains an integer T(1<=T<=20) which
means the number of test cases. Then T lines follow, each line consists
of two positive integers, A and B. Notice that the integers are very
large, that means you should not process them by using 32-bit integer.
You may assume the length of each integer will not exceed 1000.
first line of the input contains an integer T(1<=T<=20) which
means the number of test cases. Then T lines follow, each line consists
of two positive integers, A and B. Notice that the integers are very
large, that means you should not process them by using 32-bit integer.
You may assume the length of each integer will not exceed 1000.
Output
For
each test case, you should output two lines. The first line is "Case
#:", # means the number of the test case. The second line is the an
equation "A + B = Sum", Sum means the result of A + B. Note there are
some spaces int the equation. Output a blank line between two test
cases.
each test case, you should output two lines. The first line is "Case
#:", # means the number of the test case. The second line is the an
equation "A + B = Sum", Sum means the result of A + B. Note there are
some spaces int the equation. Output a blank line between two test
cases.
Sample Input
2
1 2
112233445566778899 998877665544332211
1 2
112233445566778899 998877665544332211
Sample Output
Case 1:
1 + 2 = 3
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
题意：
高精度a+b
题解
java大法好！
import java.util.*;
import java.io.*;
import java.math.*; public class Main{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int t=in.nextInt();
for(int i=;i<=t;i++)
{
if(i!=)
System.out.println();
BigInteger a = in.nextBigInteger();
BigInteger b = in.nextBigInteger();
System.out.println("Case "+i+":");
System.out.println(a+" + "+b+" = "+a.add(b));
}
}
}