我想建立一个学生姓名和科目的董事会,每个学生都有一个成绩(或者不是……他可以离开考试而不写,然后他的案子将是空的).我想只使用HashMaps.我的意思是,它会是这样的:
HashMap<String,HashMap<String,String>> bigBoard =
new HashMap<String,HashMap<String,String>>();
但我认为,我没有正确的想法,因为对于每个主题,将有许多等级(值),所以这是不可能的.我是否必须为每个学生制作地图?与他的主题?但是输出表将不会被安排.你有一个主张吗?
我想要一张看起来像这样的桌子.
Column-Key →
Rowkey↓ Mathematics Physics Finance
Daniel Dolter 1.3 3.7
Micky Mouse 5
Minnie Mouse 1.7 n/a
Dagobert Duck 4.0 1.0
(我会使用所有的键/值作为字符串,它会更简单.)
在我们的类实现之后(例如class-name是String2D),我们应该像这样使用它.
public static void main(String[] args) {
String2D map2D = new String2D();
map2D.put("Daniel Doster", "Practical Mathematics", "1.3");
map2D.put("Daniel Doster", "IT Systeme", "3.7");
map2D.put("Micky Mouse", "Finance", "5");
map2D.put("Minnie Mouse", "IT Systeme", "1.7");
map2D.put("Minnie Mouse", "Finance", "n/a");
map2D.put("Dagobert Duck", "Practical Mathematics", "4.0");
map2D.put("Dagobert Duck", "Finance", "1.0");
System.out.println(map2D);
}
不会看到“HashMap”..并且不允许使用数组
解决方法:
你可以使用这个类:
public class BiHashMap<K1, K2, V> {
private final Map<K1, Map<K2, V>> mMap;
public BiHashMap() {
mMap = new HashMap<K1, Map<K2, V>>();
}
/**
* Associates the specified value with the specified keys in this map (optional operation). If the map previously
* contained a mapping for the key, the old value is replaced by the specified value.
*
* @param key1
* the first key
* @param key2
* the second key
* @param value
* the value to be set
* @return the value previously associated with (key1,key2), or <code>null</code> if none
* @see Map#put(Object, Object)
*/
public V put(K1 key1, K2 key2, V value) {
Map<K2, V> map;
if (mMap.containsKey(key1)) {
map = mMap.get(key1);
} else {
map = new HashMap<K2, V>();
mMap.put(key1, map);
}
return map.put(key2, value);
}
/**
* Returns the value to which the specified key is mapped, or <code>null</code> if this map contains no mapping for
* the key.
*
* @param key1
* the first key whose associated value is to be returned
* @param key2
* the second key whose associated value is to be returned
* @return the value to which the specified key is mapped, or <code>null</code> if this map contains no mapping for
* the key
* @see Map#get(Object)
*/
public V get(K1 key1, K2 key2) {
if (mMap.containsKey(key1)) {
return mMap.get(key1).get(key2);
} else {
return null;
}
}
/**
* Returns <code>true</code> if this map contains a mapping for the specified key
*
* @param key1
* the first key whose presence in this map is to be tested
* @param key2
* the second key whose presence in this map is to be tested
* @return Returns true if this map contains a mapping for the specified key
* @see Map#containsKey(Object)
*/
public boolean containsKeys(K1 key1, K2 key2) {
return mMap.containsKey(key1) && mMap.get(key1).containsKey(key2);
}
public void clear() {
mMap.clear();
}
}
然后创建使用它像这样:
BiHashMap<String,String,String> bigBoard = new BiHashMap<String,String,String>();
但是对于性能,您可能希望将不同的成绩存储在一个数组中(假设您有一组修复的课程)