Poj 2777 Count Color(线段树基础)

又毁三观了.......虽然题目数据有坑:区间【a,b】可能会有a>b的情况,但是我一开始没有考虑它也能过。

此外莫名其妙的TLE

#include <iostream>
#include <algorithm>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <string>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <climits>
#define MAX 100005
#define INF 0x7FFFFFFF
#define REP(i,s,t) for(int i=(s);i<=(t);++i)
#define ll long long
#define mem(a,b) memset(a,b,sizeof(a))
#define mp(a,b) make_pair(a,b)
#define L(x) x<<1
#define R(x) x<<1|1
# define eps 1e-5
//#pragma comment(linker, "/STACK:36777216") ///传说中的外挂
using namespace std;
struct node {
int left,right,mid,value,add;
} edge[4*MAX]; int aa[MAX];
int vis[33];
int ans ;
void push_up(int x) {
if(edge[R(x)].add != edge[L(x)].add)
edge[x].add = 0;
} void build(int l,int r,int num) { edge[num].left = l;
edge[num].right = r;
edge[num].mid = (l+r) >> 1;
edge[num].add = 1;
if(l == r) {
edge[num].value = 1;
return ;
} build(l,edge[num].mid,num * 2); //左子树
build(edge[num].mid + 1,r,num*2+1); //右子树 push_up(num); } void push_down(int x) {
if(edge[x].add) {
//edge[L(x)].value = (edge[L(x)].right - edge[L(x)].left + 1 ) * edge[x].add ;
//edge[R(x)].value = (edge[R(x)].right - edge[R(x)].left + 1) * edge[x].add ;
edge[L(x)].add = edge[x].add ;
edge[R(x)].add = edge[x].add ;
edge[x].add = 0 ;
}
}
void update(int l, int r, int k, int num) {
if(edge[num].left >= l && edge[num].right <= r) {
//当前区间包含于更新区间
edge[num].add = k;
return;
}
push_down(num);
if(edge[num].mid < l) update(l, r, k, num*2+1);
else if(edge[num].mid >= r) update(l, r, k, num*2);
else {
update(l, edge[num].mid, k, num*2);
update(edge[num].mid + 1, r, k, num*2+1);
}
push_up(num); } void query(int l,int r,int num) {
//if(l == edge[num].left && r == edge[num].right) //很想知道加了这个判断后TLE,不加400ms以内是为什么,按理加它是没有问题的......
if(edge[num].add != 0) {
if(vis[edge[num].add] == 0) {
ans++;
vis[edge[num].add] = 1;
}
return ;
}
push_down(num);
if(r <= edge[num].mid)
query(l,r,num*2);
else if(l >= edge[num].mid + 1)
query(l,r,num *2+1);
else {
query(l,edge[num].mid,num*2);
query(edge[num].mid+1,r,num*2+1);
}
} int main() { int n,m,l,i,x,y,c;
char str[3] ;
cin >> n >> l >> m;
build(1,n,1);
for(i=1; i<=m; i++) {
scanf("%s",str);
if(str[0] == 'C') {
scanf("%d%d%d",&x,&y,&c);
if(x > y)
swap(x,y);
update(x,y,c,1);
}
if(str[0] == 'P') {
ans = 0;
scanf("%d%d",&x,&y);
if(x > y)
swap(x,y);
mem(vis,0);
query(x,y,1);
printf("%d\n",ans);
} }
return 0;
}
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