今天在*上看到这么个问题,写完之后看了看别人的提交的答案,感觉自己的答案虽然能得出正确结果但是有点啰嗦,对于c++还是没有熟练,没有想起有istringstream,而且提问的老外写的程序bug实在是太多了,while循环啊,分号啊都不规范,不过那个return挺有意思,嘿嘿第一次见(可能是写的代码和看的代码太少了吧 ,嘿嘿 ,见笑,我也是一菜),于是我放弃了我原来的答案,修改了一下别人的答案,那个人的答案也不对,不能运行啊,所以说我自己改动了一下.
今儿记录一下,省的以后忘..
老外的提问:
struct client
{
string PhoneNumber;
string FirstName;
string LastName;
string Age;
};
int main()
{
string data = getClientDatabase(); vector <client> clients; parse_string(data, clients);
return ;
} string getClientDatabase()
{
return
"(844)615-4504 Sofia Ross 57 \n"
"(822)516-8895 Jenna Doh 30 \n"
"(822)896-5453 Emily Saks 43 \n" } void parse_string(string data, vector <client> &clients)
{
string temp;
string temp1;
string temp2;
string temp3; int i = ;
int j = ;
int k = ;
int l = ; while (i < data.length())
{
if (data.at(i) != ' ')
{
temp.push_back(data.at(i));
j++;
}
else
{
clients.at(i).PhoneNumber = temp;
} }
if (data.at(j) != ' ')
{
temp1.push_back(data.at(j));
k++;
}
else
{
clients.at(i).FirstName = temp1;
} if (data.at(k) != ' ')
{
temp2.push_back(data.at(k));
l++;
}
else
{
clients.at(i).LastName = temp2;
} if (data.at(l) != ' ')
{
temp3.push_back(data.at(l)); }
else
{
clients.at(i).Age = temp3;
}
i++; }
我的回答:
void parse_string(string data, vector <client> & clients)
{
struct client tempS;
istringstream iss(data);
for (size_t i=; iss >> tempS.PhoneNumber; ++i)
{
iss >> tempS.FirstN >> tempS.LastN >> tempS.Age;
clients.push_back(tempS);
}
}
//test code vector <client>::iterator it = clients.begin();
for(; it != clients.end(); ++it )
{
cout << it->PhoneNumber << " "
<< it->FirstN << " "
<< it->LastN << " "
<< it->Age << endl;
}