1 SELECT 2 [UserName] 3 ,[Yhxm] 4 ,[Qx] 5 ,[Phone] 6 ,[Number] = COUNT([UserName]) 7 FROM 8 (SELECT 9 [UserName] = A.[username] 10 ,[Yhxm] = B.[xm] 11 ,[Qx] = D.[P_Power] 12 ,[Phone] = B.[dh] 13 ,[DayCount] = (SELECT COUNT(*) FROM [Caihuashun_FuJian_T] WHERE (SELECT (DATEDIFF(DAY,[F_bxsj],GETDATE()))) = 0) 14 ,[MonthCount] = (SELECT COUNT(*) FROM [Caihuashun_FuJian_T] WHERE (SELECT (DATEDIFF(MONTH,[F_bxsj],GETDATE()))) = 0) 15 FROM 16 [Caihuashun_UserInfo_T] AS [A] 17 LEFT JOIN 18 [Caihuashun_Vita_T] AS [B] 19 ON 20 A.[username] = B.[username] 21 LEFT JOIN 22 [Caihuashun_FuJian_T] AS [C] 23 ON 24 C.[F_jxy] = A.[username] 25 LEFT JOIN 26 [Caihuashun_Authority_T] AS [D] 27 ON 28 D.[P_id] = A.[power]) 29 AS [A] 30 GROUP BY [UserName],[Yhxm],[Qx],[Phone]
因为group by不能使用 where 所以我想查询UserName=452087948的那么只要在后面加上HAVING UserName =‘452087948‘ 那么查询的结果如下