在网络上,假设我们超链接地址对应于jpg档,txt档,点击链接,默认浏览器打开这些文件,而不是下载,那么,你如何实现竞争力的默认下载。
1.可通过自己写一个download.jsp来实现
<%@ page contentType="text/html; charset=UTF-8"%>
<%@ page import="java.net.*"%>
<%
//得到文件名称字和路径
String filename = request.getParameter("filename");
String filepath = request.getParameter("filepath");
String displayfilename = URLEncoder.encode(filename,"UTF-8");
try {
response.setContentType("application/x-download");
response.setHeader("Content-Disposition","attachment;filename=\"" + displayfilename + "\"");
//HttpServletContext httpServletContext = (HttpServletContext)application;
RequestDispatcher dis = application.getRequestDispatcher(filepath + filename);
//application.getRequestDispatcher(url)这里的url仅仅能是相对路径,如/upload/1.jpg
if (dis != null) {
dis.forward(request,response);
}
response.flushBuffer();
} catch (Exception e) {
e.printStackTrace();
System.out.println("下载取消:" + filepath + filename);
}
out.clear();
out = pageContext.pushBody();
%>
当我们要链接图片(或其它浏览器默认打开的格式,这里以图片为例)时。把相应的文件名称和地址传入download.jsp的filename和filepath參数里。详细写法例如以下
<a class="blue-line-a" href=" /PackTool/download.jsp? filename=WinGUI.exe&filepath=/other/WinGUI.exe">/other/WinGUI.exe</a>
通过这样方式,我们就能实现文件的默认下载了,而不是浏览器的默认打开。
2.通过文件输出流方式(推荐):
<%@ page language="java" contentType="application/x-msdownload" pageEncoding="UTF-8"%>
<%@ page import="java.net.*"%>
<%@ page import="java.io.*"%>
<%@ page import="com.hikvision.modules.guide.util.*"%>
<%
//关于文件下载时採用文件流输出的方式处理:
//加上response.reset(),而且全部的%>后面不要换行。包含最后一个;
String filename = request.getParameter("filename");
String filepath = request.getParameter("filepath");
response.reset();//能够加也能够不加
response.setContentType("application/x-download");
//"想办法找到要提供下载的文件的物理路径+文件名称";D:/PackTools/shareFolder
String filedownload = GetSharePathXml.getShareFolderPath() + filename;
//"给用户提供的下载文件名称"
String filedisplay = filename;
filedisplay = URLEncoder.encode(filedisplay,"UTF-8");
response.addHeader("Content-Disposition","attachment;filename=" + filedisplay); OutputStream outp = null;
FileInputStream in = null;
try
{
outp = response.getOutputStream();
in = new FileInputStream(filedownload); byte[] b = new byte[1024];
int i = 0; while((i = in.read(b)) > 0)
{
outp.write(b, 0, i);
}
outp.flush();
}
catch(Exception e)
{
System.out.println("Error!");
e.printStackTrace();
}
finally
{
if(in != null)
{
in.close();
in = null;
}
if(outp != null)
{
outp.close();
out.clear();
outp = null;
}
}
%>
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