1.猜年龄游戏:
要求:
允许用户最多尝试3次
每尝试3次后,如果还没猜对,就问用户是否还想继续玩,如果回答Y或y, 就继续让其猜3次,以此往复,如果回答N或n,就退出程序
如果猜对了,有三次选择奖励的机会,不要奖励可以随时退出,并打印奖品清单给用户看;
age = 18
count = 0
price_dic = {0: '布娃娃', 1: '变形金刚', 2: '奥特曼', 3: '《Python从入门到放弃》'}
while count < 3:
age_inp = input('请输入你的年龄:')
if not age_inp.isdigit():
print('输错了,请重新输入')
continue
age_inp_int = int(age_inp)
if age_inp_int == age:
print('猜对了')
print(price_dic)
for i in range(2):
prize_choice = input('请输入你想要的奖品,如果不想要,则输入"n"退出!')
if prize_choice != 'n':
print(f'恭喜你获得奖品: {price_dic[int(prize_choice)]}')
else:
break
break
elif age_inp_int < age:
print('猜小了')
else:
print('猜大了')
count += 1
if count != 3:
continue
again_choice = input('是否继续游戏,继续请输入"Y",否则任意键直接退出.')
if again_choice == 'Y':
count = 0
2.三级菜单:
- 打印省、市、县三级菜单
- 可返回上一级
- 可随时退出程序
menu = {
'北京': {
'海淀': {
'五道口': {
'soho': {},
'网易': {},
'google': {}
},
'中关村': {
'爱奇艺': {},
'汽车之家': {},
'youku': {},
},
'上地': {
'百度': {},
},
},
'昌平': {
'沙河': {
'老男孩': {},
'北航': {},
},
'天通苑': {},
'回龙观': {},
},
'朝阳': {},
'东城': {},
},
'上海': {
'闵行': {
"人民广场": {
'炸鸡店': {}
}
},
'闸北': {
'火车战': {
'携程': {}
}
},
'浦东': {},
},
'山东': {},
}
tag = True
while tag:
menu1 = menu
for key in menu1:
print(key)
choice1 = input('第一层: ').strip()
if choice1 == 'b':
break
if choice1 == 'q':
tag = False
continue
if choice1 not in menu1:
continue
while tag:
menu_2 = menu1[choice1]
for key in menu_2:
print(key)
choice2 = input('第二层: ').strip()
if choice2 == 'b':
break
if choice2 == 'q':
tag = False
continue
if choice2 not in menu_2:
continue
while tag:
menu_3 = menu_2[choice2]
for key in menu_3:
print(key)
choice3 = input('第三层: ').strip()
if choice3 == 'b':
break
if choice3 == 'q':
tag = False
continue
if choice3 not in menu_3:
continue
while tag:
menu_4 = menu_3[choice3]
for key in menu_4:
print(key)
choice4 = input('第四层: ').strip()
if choice4 == 'b':
break
if choice4 == 'q':
tag = False
continue
if choice4 not in menu_4:
continue