哈哈哈哈哈哈哈，最近一直在补题，改各种错误的代码，wa了20多遍，改到心态爆炸，改好之后，感觉世界都美好了(叉会腰~)。。。
1 second
64 megabytes
standard input
standard output
A big marathon is held on Al-Maza Road, Damascus. Runners came from all over the world to run all the way along the road in this big marathon day. The winner is the player who crosses the finish line first.
The organizers write down finish line crossing time for each player. After the end of the marathon, they had a doubt between 2 possible winners named "Player1" and "Player2". They will give you the crossing time for those players and they want you to say who is the winner?
First line contains number of test cases (1 ≤ T ≤ 100). Each of the next T lines represents one test case with 6 integers H1 M1 S1 H2 M2 S2. Where H1, M1, S1 represent Player1 crossing time (hours, minutes, seconds) and H2, M2, S2 represent Player2 crossing time (hours, minutes, seconds). You can assume that Player1 and Player2 crossing times are on the same day and they are represented in 24 hours format(0 ≤ H1,H2 ≤ 23 and 0 ≤ M1,M2,S1,S2 ≤ 59)
H1, M1, S1, H2, M2 and S2 will be represented by exactly 2 digits (leading zeros if necessary).
For each test case, you should print one line containing "Player1" if Player1 is the winner, "Player2" if Player2 is the winner or "Tie" if there is a tie.
3
18 03 04 14 03 05
09 45 33 12 03 01
06 36 03 06 36 03
Player2
Player1
Tie
代码:
#include<bits/stdc++.h>
using namespace std;
int main(){
int n;
int a,b,c,a1,b1,c1;
while(~scanf("%d",&n)){
while(n--){
scanf("%d%d%d%d%d%d",&a,&b,&c,&a1,&b1,&c1);
if(a>a1) {printf("Player2\n");}
else if(a<a1) {printf("Player1\n");}
else if(a==a1){
if(b>b1){printf("Player2\n");}
else if(b<b1){printf("Player1\n");}
else if(b==b1){
if(c>c1){printf("Player2\n");}
else if(c<c1){printf("Player1\n");}
else printf("Tie\n");
}
}
}
}
return ;
}