Sum square difference
Problem 6
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385
= 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
补充两个公式
证明：倒序相加，
证明：数学归纳法
这都是高中的题目
给出我的python代码：
n = 100 s1 = n*(n+1)/2 # sum of (1..n)1+2+....+n s2 = n*(n+1)*(2*n+1)/6 # sum of (1+2**2+3**2+...n**2) print s1**2-s2