Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3

1 2 3

2 3 4

9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false

Case #2: true

Case #3: false

思路
注意溢出的情况就行，其他情况正常比较，溢出分两种情况：
1. A > 0,B > 0, Sum = A + B 正溢出,溢出后的值Sum <= 0;
2. A < 0,B < 0, Sum = A + B 负溢出,溢出后的值Sum >= 0;

代码

#include<iostream>

#include<vector>

using namespace std;

int main()

{

    int T;

    while(cin >> T)

    {

        long long a,b,c;

        for(int i = ; i <= T; i++)

        {

            cin >> a >> b >> c;

            long long sum = a + b;

            if(a <  && b <  && sum >= ) //最小负数相加溢出

                cout << "Case #" << i <<": false" << endl;

            else if(a >  && b >  && sum <= ) //最大正数相加溢出

                cout << "Case #" << i <<": true" << endl;

            else if(sum > c)

                cout << "Case #" << i <<": true" << endl;

            else

                cout << "Case #" << i <<": false" << endl;

        }

    }

    return ;

}