题目：https://codeforces.com/contest/1551/problem/B2

题解：用map<int, vector<int> >mp;记录下标  。然后进行遍历，每个数一次性处理。

//#include <bits/stdc++.h>
#include <iostream>
#include <map>
#include <algorithm>
#include <vector>
using namespace std;
typedef long long int ll;

int ans[200005];
int main()
{
	int t;
	cin >> t;
	while (t--)
	{
		map<int, vector<int> >mp;
		int n, k;
		int s = 0;
		cin >> n >> k;
		for (int i = 0; i < n; i++)
		{
			int t;
			cin >> t;
			mp[t].push_back(i);//下标标记
			if (mp[t].size() <= k)
			{
				s++;
			}
		}
		s /= k;//每种颜色涂几次
		int color = 1;
		int all = s * k;//可以涂的数
		int t = 0;//涂了几个
		for (auto it = mp.begin(); it != mp.end(); it++)
		{
			int size = it->second.size();
			int tu = min(size, k);

			for (int i = 0; i < tu; i++)
			{
				int tpos = it->second[i];//这个数的下标
				if (t >= all)
				{
					ans[tpos] = 0;
					break;
				}
				ans[tpos] = color;
				color %= k;
				color++;
				t++;
			}
			for (int i = tu; i < size; i++)
			{
				ans[it->second[i]] = 0;
			}
		}
		for (int i = 0; i < n; i++)
		{
			cout << ans[i] << " ";
		}
		cout << endl;
	}
}