给定四种商品，分别是薯片(crisps)、爆米花(popcorn)、巧克力(chocolate)和可乐(cola)，单价分别对应为3.0元/公斤、2.5元/公斤、4.0元/公斤、3.5元/份。

首先在屏幕上显示以下菜单：

[1] crisps
[2] popcorn
[3] chocolate
[4] cola
[0] exit

用户可以输入编号1~4查询对应食品的单价。当连续查询次数超过5次时，程序应自动退出查询；不到5次而用户输入0即退出；输入其他编号，显示价格为0。

输入格式:

输入在一行中给出用户连续输入的若干个编号。

输出格式:

首先在屏幕上显示菜单。然后对应用户的每个输入，在一行中按格式“price = 价格”输出查询结果，其中价格保留一位小数。当用户连续查询次数超过5次、或主动输入0时，程序结束，显示“Thanks”。

输入样例1:

1 7 0 2



结尾无空行

输出样例1:

[1] crisps
[2] popcorn
[3] chocolate
[4] cola
[0] exit
price = 3.0
price = 0.0
Thanks结尾无空行

输入样例2:

1 2 3 3 4 4 5 6 7 8



结尾无空行

输出样例2:

[1] crisps
[2] popcorn
[3] chocolate
[4] cola
[0] exit
price = 3.0
price = 2.5
price = 4.0
price = 4.0
price = 3.5
Thanks结尾无空行

answer

#include <stdio.h>
int main(){
	double price[4] = {3.0,2.5,4.0,3.5};
	int number;
	printf("[1] crisps\n[2] popcorn\n[3] chocolate\n[4] cola\n[0] exit\n");
	for(int i = 0;i < 5;i++) {
		scanf("%d",&number);
		if(number == 0) 
			break;	
		else if(number == 1) 
			printf("price = %.1lf\n",price[number-1]);
		else if(number == 2) 
			printf("price = %.1lf\n",price[number-1]);
		else if(number == 3) 
			printf("price = %.1lf\n",price[number-1]);
		else if(number == 4) 
			printf("price = %.1lf\n",price[number-1]);
		else 
			printf("price = 0.0\n");
	}
	printf("Thanks");
	return 0;
}