#!/bin/bash

f1="$1*"

f2="$2*"

echo "第一个版本："$f1

echo "第二个版本："$f2

git log | grep "commit [0-9a-zA-Z]\{40\}"|awk 'BEGIN{count=0;} {commit[count]=$2;count++;} END{for(i=0;i<NR;i++) print i,commit[i]}' | grep -E "$f1|$f2" > result

LineNum=`awk 'END {print NR}' ./result`

if [ $LineNum -lt  ];then

echo "版本号输入错误,请检查输入的版本号"

else

num=`awk 'BEGIN{count=0;} {num[count]=$1;count++;} END{print sqrt((num[0]-num[1])*(num[0]-num[1]))+1}' ./result`

echo "相差"$num"个版本"

fi