/**
* Date类型转为指定格式的String类型
*
* @param source
* @param pattern
* @return
*/
public static String DateToString(Date source, String pattern) {
simpleDateFormat = new SimpleDateFormat(pattern);
return simpleDateFormat.format(source);
}
/**
*
* 字符串转换为对应日期
*
* @param source
* @param pattern
* @return
*/
public static Date stringToDate(String source, String pattern) {
simpleDateFormat = new SimpleDateFormat(pattern);
Date date = null;
try {
date = simpleDateFormat.parse(source);
} catch (Exception e) {
}
return date;
}
获取两个时间之间的分钟集合
public static List<String[]> findTimes(String dBegin, String dEnd) {
List<String[]> timeList = new ArrayList<String[]>();
Calendar calBegin = Calendar.getInstance();
calBegin.setTime(DateUtils.stringToDate(dBegin, "yyyyMMddHH"));
Calendar calEnd = Calendar.getInstance();
calEnd.setTime(DateUtils.stringToDate(dEnd, "yyyyMMddHH"));
String temps = null;
String tempe = null;
while (calBegin.getTime().compareTo(calEnd.getTime()) == -1) {
String[] lDate = new String[2];
temps = DateUtils.DateToString(calBegin.getTime(), "yyyyMMddHHmm");
calBegin.add(Calendar.MINUTE, 1);
tempe = DateUtils.DateToString(calBegin.getTime(), "yyyyMMddHHmm");
lDate[0] = temps;
lDate[1] = tempe;
timeList.add(lDate);
temps = tempe;
}
return timeList;
}
List<String[]> listInfo=findTimes("2017080801","2017080802");
//结果数组
[["201708080100","201708080101"],["201708080101","201708080102"],.....,["201708080158","201708080159"],["201708080159","201708080200"]]