HDU2602 Bone Collector


Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
HDU2602 Bone Collector

 

Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
 

Output
One integer per line representing the maximum of the total value (this number will be less than 231).
 

Sample Input
1 5 10 1 2 3 4 5 5 4 3 2 1
 

Sample Output
14
 

#include <iostream>
using namespace std;

int volume[1005];
int value[1005];
int dp[1005];
int n,m;

int main()
{
	freopen("C:\\in.txt","r",stdin);
	int T;
	scanf("%d",&T);
	while(T--){
		int N,V;
		memset(dp,0,sizeof(dp));
		scanf("%d %d",&N,&V);
		for(int i=1;i<=N;i++)
			scanf("%d",&value[i]);
		for(int i=1;i<=N;i++)
			scanf("%d",&volume[i]);
		for(int i=1;i<=N;i++)
			for(int j=V;j>=volume[i];j--)
				dp[j]=max(dp[j],dp[j-volume[i]]+value[i]);
		printf("%d\n",dp[V]);
	}
    return 0;
}



HDU2602 Bone Collector

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