locals() 函数会以字典类型返回当前位置的全部局部变量

createVar = locals()

listTemp = [1,2,3,4]

for i,s in enumerate(listTemp):

    createVar['a'+str(i+1)] = s

print(createVar,type(createVar))

print(a1,a2,a3,a4)

>>> 'execfile': <function execfile at 0x105095950>, 'runfile': <function runfile at 0x1051f01e0>, 'breakpoint': <function ptvsd_breakpointhook at 0x102c010d0>}, 'createVar': {...}, 'listTemp': [1, 2, 3, 4], 'i': 3, 's': 4, 'a1': 1, 'a2': 2, 'a3': 3, 'a4': 4} <class 'dict'>

1 2 3 4

locals()返回一个包含所有局部变量的字典，createVar指向这个字典。下面的操作就是往这个字典里添加数据了。

另一种方法：

word=[]

for i in range(4):

    word.append('words_{}'.format(i))

print(word)

>>>['words_0', 'words_1', 'words_2', 'words_3']

listTemp = [1,2,3,4]

word={}

for i,s in enumerate(listTemp):

    word['words_{}'.format(i)] = s

print(word)

>>> {'words_0': 1, 'words_1': 2, 'words_2': 3, 'words_3': 4}

https://www.cnblogs.com/technologylife/p/9211324.html