Java中静态数据的初始化顺序

Java的类中的数据成员中包含有静态成员(static)时,静态数据成员的初始化顺序是怎样的呢?

【程序实例1】

import java.util.*;
import java.lang.*;
import java.io.*; /* Name of the class has to be "Main" only if the class is public. */ class Bowl {
Bowl(int marker) {
System.out.println("Bowl("+marker+")");
}
void f1(int marker) {
System.out.println("f1("+marker+")");
}
} class Table {
static Bowl bowl1=new Bowl(1);
Table() {
System.out.println("Table()");
bowl2.f1(1);
}
void f2(int marker){
System.out.println("f2("+marker+")");
}
static Bowl bowl2=new Bowl(2);
} class Cupboard {
Bowl bowl3=new Bowl(3);
static Bowl bowl4=new Bowl(4);
Cupboard() {
System.out.println("Cupboard()");
bowl4.f1(2);
}
void f3(int marker) {
System.out.println("f3("+marker+")");
}
static Bowl bowl5=new Bowl(5);
} class Ideone
{
public static void main (String[] args) //throws java.lang.Exception
{
System.out.println("Creating new Cupboard() in main");
new Cupboard();
System.out.println("Creating new Cupboard() in main");
new Cupboard();
table.f2(1);
cupboard.f3(1);
} static Table table=new Table();
static Cupboard cupboard=new Cupboard();
}

【运行结果】

Bowl(1)
Bowl(2)
Table()
f1(1)
Bowl(4)
Bowl(5)
Bowl(3)
Cupboard()
f1(2)
Creating new Cupboard() in main
Bowl(3)
Cupboard()
f1(2)
Creating new Cupboard() in main
Bowl(3)
Cupboard()
f1(2)
f2(1)
f3(1)

从上面的执行结果可以看出:

  在初始化变量时,Java中static数据成员初始化优先于局部变量,先按定义的顺序初始化静态变量,然后是局部变量,最后执行类的构造函数。

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