写完上一篇文章后，陆续有朋友给出了其他思路，我在小结在这篇博客中。
思路一：转换成字符串后输出（这也是上一篇文章给的思路）
1 1 SELECT CASE WHEN @a % @b = 0 THEN CAST(@a / @b AS VARCHAR(16)) 2 2 ELSE CAST(CAST(@a * 1.0 / @b AS DECIMAL(10,4)) AS VARCHAR(32)) END ‘12 / 5‘, 3 3 CASE WHEN @c % @d = 0 THEN CAST(@c / @d AS VARCHAR(16)) 4 4 ELSE CAST(CAST(@c * 1.0 / @d AS DECIMAL(10,4)) AS VARCHAR(32)) END ‘12 / 3‘
思路二：使用Replace()函数来判断小数点后面的形式
1 DECLARE @a INT,@b INT,@c INT,@d INT 2 SET @a = 12 3 SET @b = 5 4 SET @c = 12 5 SET @d = 3 6 SELECT REPLACE(CAST(@a * 1.0 / @b AS DECIMAL(10,4)),‘.0000‘,‘‘) ‘12 / 5‘, 7 REPLACE(CAST(@c * 1.0 / @d AS DECIMAL(10,4)),‘.0000‘,‘‘) ‘12 / 3‘
思路三：使用Round()函数判断四舍五入后的结果与原始结果是否相等
1 DECLARE @a INT,@b INT,@c INT,@d INT 2 SET @a = 12 3 SET @b = 5 4 SET @c = 12 5 SET @d = 3 6 SELECT CASE WHEN ROUND(@a * 1.0 / @b,0) = @a * 1.0 / @b THEN CAST(@a / @b AS VARCHAR(16)) 7 ELSE CAST(CAST(@a * 1.0 / @b AS DECIMAL(10,4)) AS VARCHAR(32)) END ‘12 / 5‘, 8 9 CASE WHEN ROUND(@c * 1.0 / @d,0) = @c * 1.0 / @d THEN CAST(@c / @d AS VARCHAR(16)) 10 ELSE CAST(CAST(@c * 1.0 / @d AS DECIMAL(10,4)) AS VARCHAR(32)) END ‘12 / 3‘
以上三种思路的运行结果都是：