剑指 Offer 12. 矩阵中的路径

剑指 Offer 12. 矩阵中的路径

  public boolean exist(char[][] board, String word) {
        if (board == null || board.length == 0 || board[0].length == 0) {
            return false;
        }

        char[] chars = word.toCharArray();
        boolean[][] visited = new boolean[board.length][board[0].length];
        for (int i = 0; i < board.length; i++) {
            for (int j = 0; j < board[0].length; j++) {
                // 从 (0, 0) 点开始进行 dfs 操作,不断地去找,
                // 如果以 (0, 0) 点没有对应的路径的话,那么就从 (0, 1) 点开始去找
                if (dfs(board, chars, visited, i, j, 0)) {
                    return true;
                }
            }
        }
        return false;
    }

    private boolean dfs(char[][] board, char[] chars, boolean[][] visited, int i, int j, int start) {
        if (i < 0 || i >= board.length || j < 0 || j >= board[0].length 
                || chars[start] != board[i][j] || visited[i][j]) {
            return false;
        }
        if (start == chars.length - 1) {
            return true;    
        }
        visited[i][j] = true;
        boolean ans = false;
        ans = dfs(board, chars, visited, i + 1, j, start + 1) 
           || dfs(board, chars, visited, i - 1, j, start + 1)
           || dfs(board, chars, visited, i, j + 1, start + 1)
           || dfs(board, chars, visited, i, j - 1, start + 1);
        visited[i][j] = false;
        return ans;
    }
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