如何使用C#获取Win7的SSID和RSSI

我是Win7和WMI的新手.请告诉我从WiFi到哪里查看有效接入点以及如何为每个接入点获取ssid / rssi.

我用过:

ManagementClass mc = new ManagementClass("root\\WMI", "MSNdis_80211_ServiceSetIdentifier", null);          
ManagementObjectSearcher searcher1 = new ManagementObjectSearcher(@"root\wmi","SELECT * FROM MSNdis_80211_BSSIList");

但我得到0结果.这个类是否支持Win7?有人可以帮忙吗?

解决方法:

我有一个类似的问题,我需要获得当前连接的Wifi网络的SSID但不想因为它的复杂性而为API创建包装器所以想到为什么不使用netsh

        ProcessStartInfo info = new ProcessStartInfo("netsh", "wlan show interfaces");
        info.WorkingDirectory = @"%WINDIR%\system32";
        info.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
        info.CreateNoWindow = true;
        info.RedirectStandardOutput = true;
        info.UseShellExecute = false;
        System.Diagnostics.Process proc = new System.Diagnostics.Process();
        proc.StartInfo = info;
        proc.Start();

然后你可以从proc.StandardOutput.ReadToEnd()中检索输出;
从字符串中解析出你想要的东西:

"\r\n There is 1 interface on the system: \r\n\r\n
Name                   : Wireless Network Connection\r\n
Description            : Atheros AR9285 Wireless Network Adapter\r\n
GUID                   : xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx\r\n
Physical address       : xx:xx:xx:xx:xx:xx\r\n
State                  : connected\r\n
SSID                   : Dynex2\r\n
BSSID                  : xx:xx:xx:xx:xx:xx\r\n
Network type           : Infrastructure\r\n
Radio type             : 802.11g\r\n
Authentication         : WPA2-Personal\r\n
Cipher                 : CCMP\r\n
Connection mode        : Auto Connect\r\n
Channel                : 1\r\n
Receive rate (Mbps)    : 54\r\n
Transmit rate (Mbps)   : 54\r\n
Signal                 : 100% \r\n
Profile                : Dynex2 \r\n\r\n
Hosted network status  : Not available\r\n\r\n"

解析字符串比编写API的包装容易得多
希望这可以帮助

上一篇:数据算法第三章中的问题你面试和工作中遇到过吗?


下一篇:本征半导体与PN结