People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.
Input Specification:
Each input file contains one test case which occupies a line containing the three decimal color values.
Output Specification:
For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.
题意：
三个数分别转十三进制
AC代码：
#include <iostream>
using namespace std;
int main(){
char ans[13];
for(int i=0;i<10;i++) ans[i]=i+'0';
ans[10]='A',ans[11]='B',ans[12]='C';
int a[3];
for(int i=0;i<3;i++) cin>>a[i];
cout<<"#";
for(int i=0;i<3;i++){
cout<<ans[a[i]/13]<<ans[a[i]%13];
}
return 0;
}
#include<bits/stdc++.h>
using namespace std;
char d[15]={'0','1','2','3','4','5','6','7','8','9','A','B','C'};
int main(){
int a[5];
cin>>a[1]>>a[2]>>a[3];
cout<<"#";
for(int i=1;i<=3;i++)
{
int x=a[i];
int b[5];
int k=0;
//转成13进制
while(x>=13){
b[++k] = x/13;
x=x%13;
}
b[++k]=x;
if(k==1){
cout<<0<<d[b[1]];
}else{
cout<<d[b[1]]<<d[b[2]];
}
}
return 0;
}
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