我正在使用InputFilter类来制作支持数字分组的蒙版EditText.例如,当用户插入“12345”时,我想在EditText中显示“12,345”.我该如何实现它?
这是我不完整的代码:
InputFilter IF = new InputFilter() {
@Override
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend) {
for (int i = start; i < end; i++) {
if (!Character.isLetterOrDigit(source.charAt(i))) {
return "";
}
}
if (dest.length() > 0 && dest.length() % 3 == 0)
{
return "," + source;
}
return null;
}
};
edtRadius.setFilters(new InputFilter[] { IF });
有没有其他方法来实现这种输入掩码?
解决方法:
这是@vincent响应的改进.它添加了对1234 5678 9190格式中删除空格的检查,因此在尝试删除空格时,只需将光标后面的字符移动到空格前的数字即可.即使插入空格,它也会将光标保持在相同的相对位置.
mTxtCardNumber.addTextChangedListener(new TextWatcher() {
private boolean spaceDeleted;
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
// check if a space was deleted
CharSequence charDeleted = s.subSequence(start, start + count);
spaceDeleted = " ".equals(charDeleted.toString());
}
public void afterTextChanged(Editable editable) {
// disable text watcher
mTxtCardNumber.removeTextChangedListener(this);
// record cursor position as setting the text in the textview
// places the cursor at the end
int cursorPosition = mTxtCardNumber.getSelectionStart();
String withSpaces = formatText(editable);
mTxtCardNumber.setText(withSpaces);
// set the cursor at the last position + the spaces added since the
// space are always added before the cursor
mTxtCardNumber.setSelection(cursorPosition + (withSpaces.length() - editable.length()));
// if a space was deleted also deleted just move the cursor
// before the space
if (spaceDeleted) {
mTxtCardNumber.setSelection(mTxtCardNumber.getSelectionStart() - 1);
spaceDeleted = false;
}
// enable text watcher
mTxtCardNumber.addTextChangedListener(this);
}
private String formatText(CharSequence text)
{
StringBuilder formatted = new StringBuilder();
int count = 0;
for (int i = 0; i < text.length(); ++i)
{
if (Character.isDigit(text.charAt(i)))
{
if (count % 4 == 0 && count > 0)
formatted.append(" ");
formatted.append(text.charAt(i));
++count;
}
}
return formatted.toString();
}
});