获取 code 分组中 max(version) max(batch) 最大的 记录
``` CREATE TABLE t ( `id` int(11) , `code` int(11) , `version` int(11) , `batch` int(11) ) insert into t values(1, 1, 1, 1); insert into t values(2, 1, 2, 2); insert into t values(3, 1, 3, 3); insert into t values(4, 2, 1, 1); insert into t values(5, 2, 1, 1); insert into t values(6, 3, 1, 1); insert into t values(7, 3, 1, 3); select id,code,version,batch from (select t_tmp.code, t_tmp.version, t_tmp.batch, t_tmp.id, @rownum:=@rownum+1, if(@pdept=t_tmp.code,@rank:=@rank+1,@rank:=1) as rank, @pdept:=t_tmp.code from (select code,id,version,batch from t order by code,version desc, batch desc ) t_tmp , (select @rownum :=0,@pdept := null ,@rank:=0) a ) a where rank=1 ; --- 解释 select id,code,version,batch from ( select t_tmp.code, t_tmp.version, t_tmp.batch, t_tmp.id, -- 每行+1 @rownum:=@rownum+1, -- 如果变量的值等于code的值 排名+1, 如果不等于就是1(@pdept记录的是上一行的code值) if(@pdept=t_tmp.code,@rank:=@rank+1,@rank:=1) as rank, -- 这个变量的值等于行中code的值 @pdept:=t_tmp.code from (select code,id,version,batch from t order by code,version desc, batch desc ) t_tmp , -- mysql定义变量 下面这句话,初始化下面变量的值 (select @rownum :=0,@pdept := null ,@rank:=0) a ) a -- 排名第一的选出来 where rank=1;