Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
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利用双指针思想
int removeElement(vector<int>& nums, int val) {
int slow = , fast = ;
while (fast < nums.size())
{
if (nums[fast] != val)
nums[slow++] = nums[fast];
fast++;
}
return slow;
}