由题可得，现在有14个广播域，需要划分出十四个网段，需要借用四位主机位用于网络位，划分出的网段分别是：

192.168.1.0/28

192.168.1.16/28

192.168.1.32/28

192.168.1.48/28

192.168.1.64/28

192.168.1.80/28

192.168.1.96/28

192.168.1.112/28

192.168.1.128/28

192.168.1.144/28

192.168.1.160/28

192.168.1.176/28

192.168.1.192/28

192.168.1.208/28

192.168.1.224/28

192.168.1.240/28

以下为网段、网关分配情况

 

根据分析，在路由器上配置IP及环回IP

[r2]interface GigabitEthernet 0/0/0

[r2-GigabitEthernet0/0/0]ip address 192.168.1.2 28

环回

[r2]interface LoopBack 0

[r2-LoopBack0]ip address 192.168.1.65 28

因为需要全网可达，除去直连的路由器，其他的需要编写静态路由

[r1]ip route-static 192.168.1.128 27 192.168.1.18

[r1]ip route-static 192.168.1.128 27 192.168.1.2

[r1]ip route-static 192.168.1.192 27 192.168.1.18

[r1]ip route-static 192.168.1.192 27 192.168.1.2

[r1]ip route-static 192.168.1.176 28 192.168.1.18

[r1]ip route-static 192.168.1.160 28 192.168.1.2

[r4]ip route-static 192.168.1.32 27 192.168.1.161

[r4]ip route-static 192.168.1.64 27 192.168.1.161

[r4]ip route-static 192.168.1.96 27 192.168.1.177

[r4]ip route-static 192.168.1.32 27 192.168.1.177

[r4]ip route-static 192.168.1.16 28 192.168.1.177

[r4]ip route-static 192.168.1.0 28 192.168.1.161

[r3]ip route-static 192.168.1.32 27 192.168.1.17

[r3]ip route-static 192.168.1.64 27 192.168.1.17

[r3]ip route-static 192.168.1.64 27 192.168.1.178

[r3]ip route-static 192.168.1.0 28 192.168.1.17

[r3]ip route-static 192.168.1.128 27 192.168.1.178

[r3]ip route-static 192.168.1.192 27 192.168.1.178

[r3]ip route-static 192.168.1.160 28 192.168.1.178

[r2]ip route-static 192.168.1.32 27 192.168.1.1

[r2]ip route-static 192.168.1.16 28 192.168.1.1

[r2]ip route-static 192.168.1.96 27 192.168.1.1

[r2]ip route-static 192.168.1.176 28 192.168.1.1

[r2]ip route-static 192.168.1.128 27 192.168.1.162

[r2]ip route-static 192.168.1.96 27 192.168.1.162

[r2]ip route-static 192.168.1.192 27 192.168.1.162

[r2]ip route-static 192.168.1.176 28 192.168.1.162

[r5]ip route-static 192.168.1.32 27 192.168.1.193

[r5]ip route-static 192.168.1.0 28 192.168.1.193

[r5]ip route-static 192.168.1.64 27 192.168.1.193

[r5]ip route-static 192.168.1.96 27 192.168.1.193

[r5]ip route-static 192.168.1.16 28 192.168.1.193

[r5]ip route-static 192.168.1.128 27 192.168.1.193

[r5]ip route-static 192.168.1.160 28 192.168.1.193

[r5]ip route-static 192.168.1.176 28 192.168.1.193

[r5]ip route-static 192.168.1.32 27 192.168.1.209

[r5]ip route-static 192.168.1.0 28 192.168.1.209

[r5]ip route-static 192.168.1.64 27 192.168.1.209

[r5]ip route-static 192.168.1.96 27 192.168.1.209

[r5]ip route-static 192.168.1.16 28 192.168.1.209

[r5]ip route-static 192.168.1.128 27 192.168.1.209

[r5]ip route-static 192.168.1.160 28 192.168.1.209

[r5]ip route-static 192.168.1.176 28 192.168.1.209

由于R4,R5之间两条路线的带宽不一样，所以为100M的路线设置低一些的优先级，使R4,R5之间的通信优先1000M路线，故障时才使用100M路线

[r5]ip route-static 192.168.1.32 27 192.168.1.209 preference 66

[r5]ip route-static 192.168.1.0 28 192.168.1.209 preference 66

[r5]ip route-static 192.168.1.64 27 192.168.1.209 preference 66

[r5]ip route-static 192.168.1.96 27 192.168.1.209 preference 66

[r5]ip route-static 192.168.1.16 28 192.168.1.209 preference 66

[r5]ip route-static 192.168.1.128 27 192.168.1.209 preference 66

[r5]ip route-static 192.168.1.160 28 192.168.1.209 preference 66

[r5]ip route-static 192.168.1.176 28 192.168.1.209 preference 66

由于不能直接指向R5的环回使用下一跳，所以这边使用缺省路由来实现，但是有两个网段没有使用，会造成路由黑洞，所以这里使用空接口路由来处理

给R5写上

ip route-static 192.168.1.224 27 NULL 0

解决完路由黑洞，用缺省路由实现到R5环回5.5.5.0网段的可达

ip route-static 0.0.0.0 0.0.0.0 192.168.1.194

还需要考虑到优先级的问题，降低100M这个路线的优先级

ip route-static 0.0.0.0 0.0.0.0 192.168.1.194 preference 66