res = [{‘id‘: 1, ‘type‘: 1, ‘value‘: 1.9}, {‘id‘: 2, ‘type‘: 2, ‘value‘: 2.9}, {‘id‘: 2, ‘type‘: 4, ‘value‘: 3.9},
      {‘id‘: 1, ‘type‘: 2, ‘value‘: 2.9}, {‘id‘: 2, ‘type‘: 3, ‘value‘: 3.9}]
rem = [{‘r_id‘: 1, ‘name‘: ‘小白‘, ‘sex‘: ‘男‘}, {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘},
      {‘r_id‘: 4, ‘name‘: ‘黑铁疙瘩‘, ‘sex‘: ‘女‘}]

# 需求：通过r_id与id，获取不同的type对应的value值

# ret = []
#
# for i in res:
#  for j in rem:
#     if i[‘id‘] == j[‘r_id‘]:
#        j[‘type‘] = i[‘type‘]
#        j[‘value‘] = i[‘value‘]
#        ret.append(j)
#     else:
#        if j not in ret:
#           ret.append(j)
# print(ret)


获取到的结果是：

"""
[{‘r_id‘: 1, ‘name‘: ‘小白‘, ‘sex‘: ‘男‘, ‘type‘: 2, ‘value‘: 2.9},
 {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 3, ‘value‘: 3.9},
  {‘r_id‘: 4, ‘name‘: ‘黑铁疙瘩‘, ‘sex‘: ‘女‘},
   {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 3, ‘value‘: 3.9},
    {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 3, ‘value‘: 3.9},
     {‘r_id‘: 1, ‘name‘: ‘小白‘, ‘sex‘: ‘男‘, ‘type‘: 2, ‘value‘: 2.9},
      {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 3, ‘value‘: 3.9}]
"""

查看到发现是id地址重复问题

ret = []
import copy

for i in res:
   for j in rem:
      if i[‘id‘] == j[‘r_id‘]:
         j[‘type‘] = i[‘type‘]
         j[‘value‘] = i[‘value‘]
         b = j.copy().copy()
         ret.append(b)
      # print(j)
      # print(i)
      else:
         if j not in ret:
            ret.append(j)
print(ret)

"""
[{‘r_id‘: 1, ‘name‘: ‘小白‘, ‘sex‘: ‘男‘, ‘type‘: 1, ‘value‘: 1.9},
 {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 3, ‘value‘: 3.9},
  {‘r_id‘: 4, ‘name‘: ‘黑铁疙瘩‘, ‘sex‘: ‘女‘},
   {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 2, ‘value‘: 2.9},
    {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 4, ‘value‘: 3.9},
     {‘r_id‘: 1, ‘name‘: ‘小白‘, ‘sex‘: ‘男‘, ‘type‘: 2, ‘value‘: 2.9},
      {‘r_id‘: 2, ‘name‘: ‘小黑‘, ‘sex‘: ‘女‘, ‘type‘: 3, ‘value‘: 3.9}]
"""

两层循环添加列表元素之后，发现数据一致（id地址问题！）。