SQL练习题22:获取所有非manager员工当前的薪水情况,给出dept_no、emp_no以及salary ,当前表示to_date='9999-01-01'

题目:

获取所有非manager员工当前的薪水情况,给出dept_no、emp_no以及salary ,当前表示to_date=‘9999-01-01‘
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

程序:

SELECT a.dept_no, b.emp_no, c.salary
FROM dept_emp AS a INNER JOIN employees AS b
ON a.emp_no = b.emp_no
INNER JOIN salaries AS c
ON b.emp_no = c.emp_no
WHERE b.emp_no NOT IN
(SELECT emp_no FROM dept_manager)
AND c.to_date = ‘9999-01-01‘

 

SQL练习题22:获取所有非manager员工当前的薪水情况,给出dept_no、emp_no以及salary ,当前表示to_date='9999-01-01'

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