Given two binary strings, return their sum (also a binary string).
For example,
a
= "11"
b
= "1"
Return "100"
.
StringBuilder + reverse method
public class Solution { public String addBinary(String a, String b) { if(a == null || a.equals("")) return b; if(b == null || b.equals("")) return a; StringBuilder a1 = new StringBuilder(a); a1.reverse(); StringBuilder b1 = new StringBuilder(b); b1.reverse(); StringBuilder result = new StringBuilder(); int len = Math.max(a.length(), b.length()); int carry = 0; for(int i = 0; i < len ; i++){ int t1 = (i >= a.length()? 0 : (a1.charAt(i) - ‘0‘)); int t2 = (i >= b.length()? 0 : (b1.charAt(i) - ‘0‘)); int t3 = t1+t2+carry; carry = t3/2; t3 = t3%2; result.append(t3); } if(carry != 0){ result.append(carry); } result.reverse(); return result.toString(); } }