解析数据(正则,xpath)

正则表达式拆分

import re

# 1.拆分字符串
one = 'asdsfsgsh' # 标准 是 s 为拆分 pattern = re.compile('s')
result = pattern.split(one)
# print(result) # 2.匹配中文
two = '<a href="https://www.baidu.com/" nslog="normal" nslog-type="10600112" data-href="https://www.baidu.com/s?ie=utf-8&amp;fr=bks0000&amp;wd=">网页是最新版本的,适配移动端</a>' # python中 匹配中问 [a-z] unicode的范围 * + ?
pattern = re.compile('[\u4e00-\u9fa5]+') result = pattern.findall(two)
print(result)
import re
import requests url = 'http://news.baidu.com/'
headers = {
"User-Agent": 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36'
} # response.text 不太准确 转码 是靠推测
data = requests.get(url, headers=headers).content.decode() # 正则解析 数据
# 每个新闻的titile, url # <a href="http://news.cnr.cn/native/gd/20181028/t20181028_524397644.shtml" target="_blank" mon="r=1">民营经济再吃定心丸,民企当体会怎样深意</a> pattern = re.compile('<a href="(.*?)" target="_blank" mon="(.*?)">(.*?)</a>')
# pattern = re.compile('<a (.*?)</a>',re.S) result = pattern.findall(data) print(result) # with open('02news.html', 'w') as f:
# f.write(data)
xpath解析
import re
import requests # 安装支持 解析html和XML的解析库 lxml
# pip install lxml
from lxml import etree url = 'http://news.baidu.com/'
headers = {
"User-Agent": 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36'
} # response.text 不太准确 转码 是靠推测
data = requests.get(url, headers=headers).content.decode() # 1.转解析类型
xpath_data = etree.HTML(data) # xpath 语法 1. 节点 /
# 2. 跨节点: //
# 3. 精确的标签: //a[@属性="属性值"]
# 4. 标签包裹的内容 text()
# 5. 属性:@href
# xpath--s数据类型---list
# 2调用 xpath的方法
result = xpath_data.xpath('/html/head/title//text()')
result = xpath_data.xpath('//a/text()')
result = xpath_data.xpath('//a[@mon="ct=1&a=2&c=top&pn=18"]/text()')
result = xpath_data.xpath('//a[@mon="ct=1&a=2&c=top&pn=18"]/@href')
result = xpath_data.xpath('//li/a/text()') print(result) # with open('02news.html', 'w') as f:
# f.write(data)

注意事项

from  lxml import etree

html = """
<html>
<body>
<ul>
<li>1
<a href="">子</a>
</li>
<li>2
<a href="">子</a>
</li>
<li>3
<a href="">子</a>
</li>
<li>4
<a href="">子</a>
</li>
<li>5
<a href="">子</a>
</li> </ul>
</body>
</html>
"""
# 1.转类型
x_data = etree.HTML(html) # 2.xpath 下标 是从 1开始; 只能取 平级关系的标签
result = x_data.xpath('//li[5]/text()') result = x_data.xpath('/html/body/ul/li/a/text()')
result = x_data.xpath('//a[2]') print(result)

拆分实例

import requests
from lxml import etree
import json class BtcSpider(object):
def __init__(self):
self.base_url = 'http://8btc.com/forum-61-'
self.headers = {
"User-Agent": 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36'
} self.data_list = [] # 1.发请求
def get_response(self, url):
response = requests.get(url, headers=self.headers)
# 网页的 编码到底 是 gbk 还是 urf-8 head--meta-charset=""
# 原因 是 抓取 网页的 编码 就是 gbk的 所以 解码的时候 也是要gbk
# data = response.content.decode('gbk')
data = response.content
return data # 2.解析数据
def parse_data(self, data):
# 使用xpath 解析当前页面 所有的 新闻title 和url 保存
# 1.转类型
x_data = etree.HTML(data) # 2.根据xpath路径解析
# 路径 1. 纯手写 2. 借助浏览器的 右击 粘贴xpath路径; 需要修改
title_list = x_data.xpath('//a[@class="s xst"]/text()')
# title_list = x_data.xpath('//form[@id="moderate"]/div/div[2]/div/a[@class="s xst"]/text()')
url_list = x_data.xpath('//a[@class="s xst"]/@href') for index, title in enumerate(title_list):
news = {}
# print(index)
# print(title)
news['name'] = title
news['url'] = url_list[index]
self.data_list.append(news) # 3.保存数据
def save_data(self): # 将 list---str
data_str = json.dumps(self.data_list)
with open('05btc.json', 'w') as f:
f.write(data_str) # 4.启动
def run(self): for i in range(1, 5):
# 1.拼接 完整url
url = self.base_url + str(i) + '.html'
print(url)
# 2.发请求
data = self.get_response(url) # 3.做解析
self.parse_data(data)
# 4.保存
self.save_data() BtcSpider().run()
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