题意:
从n个数中任选一些数,问有多少种选法使他们异或和不小于M
思路:
dp[i][j]表示选i个数异或和为j,则方程dp[i][j] = dp[i-1][j](不选i)+ dp[i-1][j^a[i]]
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
using namespace std;
typedef long long ll;
const int maxn = 2e6 + 5;
int dp[41][maxn];
int a[41];
int main()
{
int T,n,m;
scanf("%d",&T);
int cas = 1;
while(T--)
{
scanf("%d%d",&n,&m);
for(int i = 1;i <= n;i++)
{
scanf("%d",&a[i]);
}
memset(dp,0,sizeof(dp));
dp[0][0] = 1;
int Max=(1<<20);
for(int i = 1;i <= n;i++)
{
for(int j = 0;j <= Max;j++)
dp[i][j] = dp[i-1][j] + dp[i-1][j^a[i]];
}
ll ans = 0;
for(int i = m;i <= Max;i++)
ans += dp[n][i];
printf("Case #%d: %I64d\n",cas++,ans);
}
return 0;
}