【c语言】模拟实现库函数的atof函数

//  模拟实现库函数的atof函数

#include <stdio.h>
#include <string.h>
#include <assert.h>
#include <ctype.h> double my_atof(char const *p)
{
double ret = 0;
int flag = 1;
int count = 0;
assert(p != NULL);
while (isspace(*p))
{
p++;
}
while (*p)
{
if (count)
{
count = count * 10;
}
if (*p == '+')
p++;
else if (*p == '-')
{
p++;
flag = -1;
}
else if (*p == '.')
{
count++;
p++;
}
else if (*p >= '0'&& *p <= '9')
{
ret = ret * 10 + (*p - '0');
p++;
}
else
return 0;
}
return ret*flag / count;
} int main()
{
printf("%f\n", my_atof(" +23.45"));
printf("%f\n", my_atof(" -2.345"));
printf("%f\n", my_atof("+234.5"));
printf("%f\n", my_atof("-23.45"));
printf("%f\n", my_atof("2.345"));
printf("%f\n", my_atof("234.5"));
printf("%f\n", my_atof(" ."));
printf("%f\n", my_atof("12.3ab"));
return 0;
} <img src="http://img.blog.csdn.net/20150704160911903?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQv/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/Center" alt="" />
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