1、取得每个部门最高薪水的人员名称
第一步取得每个部门最高薪水
select deptno,max(sal) as maxsal from emp group by deptno;
mysql> select deptno,max(sal) as maxsal from emp group by deptno;
±-------±--------+
| deptno | maxsal |
±-------±--------+
| 10 | 5000.00 |
| 20 | 3000.00 |
| 30 | 2850.00 |
±-------±--------+
第二步 用表上表做临时表 t ，t和emp表连接，条件t.deptno = e.deptno and t.maxsal = e.sal
select ename,t.* from (select deptno,max(sal) as maxsal from emp group by deptno) t
join emp e on t.deptno = e.deptno and t.maxsal = e.sal;
±------±-------±--------+
| ename | deptno | maxsal |
±------±-------±--------+
| KING | 10 | 5000.00 |
| SCOTT | 20 | 3000.00 |
| FORD | 20 | 3000.00 |
| BLAKE | 30 | 2850.00 |
±------±-------±--------+
2、哪些人的薪水在部门的平均薪水之上
第一步先算出部门的平均薪水
select deptno,avg(sal) as avg_sal from emp group by deptno;
±-------±------------+
| deptno | avg(sal) |
±-------±------------+
| 10 | 2916.666667 |
| 20 | 2175.000000 |
| 30 | 1566.666667 |
±-------±------------+
第二步
select t.*,e.ename,e.sal from (select deptno,avg(sal) as avg_sal from emp group by deptno) t join emp e on e.deptno = t .deptno and sal>avg_sal;
±-------±------------±------±--------+
| deptno | avg_sal | ename | sal |
±-------±------------±------±--------+
| 30 | 1566.666667 | ALLEN | 1600.00 |
| 20 | 2175.000000 | JONES | 2975.00 |
| 30 | 1566.666667 | BLAKE | 2850.00 |
| 20 | 2175.000000 | SCOTT | 3000.00 |
| 10 | 2916.666667 | KING | 5000.00 |
| 20 | 2175.000000 | FORD | 3000.00 |
±-------±------------±------±--------+
3、取得部门中（所有人的）平均的薪水等级，如下：
第一步 获取每个人的薪水等级
select e.ename,e.sal,e.deptno,s.grade from emp e join salgrade s on e.sal between s.losal and s.hisal ;
±-------±--------±-------±------+
| ename | sal | deptno | grade |
±-------±--------±-------±------+
| CLARK | 2450.00 | 10 | 4 |
| KING | 5000.00 | 10 | 5 |
| MILLER | 1300.00 | 10 | 2 |
| SCOTT | 3000.00 | 20 | 4 |
| FORD | 3000.00 | 20 | 4 |
| JONES | 2975.00 | 20 | 4 |
| SMITH | 800.00 | 20 | 1 |
| ADAMS | 1100.00 | 20 | 1 |
| JAMES | 950.00 | 30 | 1 |
| WARD | 1250.00 | 30 | 2 |
| MARTIN | 1250.00 | 30 | 2 |
| TURNER | 1500.00 | 30 | 3 |
| BLAKE | 2850.00 | 30 | 4 |
| ALLEN | 1600.00 | 30 | 3 |
±-------±--------±-------±------+
select e.deptno,avg(s.grade) from emp e join salgrade s on e.sal between s.losal and s.hisal group by e.deptno;
±-------±-------------+
| deptno | avg(s.grade) |
±-------±-------------+
| 10 | 3.6667 |
| 20 | 2.8000 |
| 30 | 2.5000 |
±-------±-------------+
4、不准用组函数（Max），取得最高薪水
select ename,sal from emp order by sal desc limit 1;
±------±--------+
| ename | sal |
±------±--------+
| KING | 5000.00 |
±------±--------+
5、取得平均薪水最高的部门的部门编号
第一部 计算每个部门的平均薪水并排序
select deptno,avg(sal) as avg_sal from emp group by deptno order by avg_sal desc limit 1;
mysql> select deptno,avg(sal) as avg_sal from emp group by deptno order by avg_sal desc limit 1;
±-------±------------+
| deptno | avg_sal |
±-------±------------+
| 10 | 2916.666667 |
±-------±------------+
6、取得平均薪水最高的部门的部门名称
select d.dname,avg(e.sal) as avg_sal from emp e join dept d on e.deptno = d.deptno group by d.dname order by avg_sal desc limit 1;
±-----------±------------+
| dname | avg_sal |
±-----------±------------+
| ACCOUNTING | 2916.666667 |
±-----------±------------+
7、求平均薪水的等级最低的部门的部门名称
1.找出每个部门的平均薪水
select d.dname,avg(e.sal) as avgsal from emp e join dept d on e.deptno =d.deptno group by e.deptno;
±-----------±------------+
| dname | avgsal |
±-----------±------------+
| ACCOUNTING | 2916.666667 |
| RESEARCH | 2175.000000 |
| SALES | 1566.666667 |
±-----------±------------+
2.找出每个部门的平均薪水的等级
select t.*,s.grade from (select d.dname,avg(e.sal) as avgsal from emp e join dept d on e.deptno =d.deptno group by e.deptno) t join salgrade s on t.avgsal between s.losal and s.hisal order by t.avgsal limit 1 ;
±------±------------±------+
| dname | avgsal | grade |
±------±------------±------+
| SALES | 1566.666667 | 3 |
±------±------------±------+
8、取得比普通员工(员工代码没有在mgr字段上出现的)的最高薪水还要高的*姓名
员工编号没有在mgr的
select distinct mgr from emp where mgr is not null;
±-----+
| mgr |
±-----+
| 7902 |
| 7698 |
| 7839 |
| 7566 |
| 7788 |
| 7782 |
±-----+
找出普通员工的最高薪水
select max(sal) from emp where empno not in (select distinct mgr from emp where mgr is not null);
±---------+
| max(sal) |
±---------+
| 1600.00 |
±---------+
找出高于（普通员工的最高薪水）
select ename,sal from emp where sal>(select max(sal) from emp where empno not in (select distinct mgr from emp where mgr is not null));
±------±--------+
| ename | sal |
±------±--------+
| JONES | 2975.00 |
| BLAKE | 2850.00 |
| CLARK | 2450.00 |
| SCOTT | 3000.00 |
| KING | 5000.00 |
| FORD | 3000.00 |
±------±--------+
9、取得薪水最高的前五名员工
select ename,sal from emp order by sal desc limit 5;
mysql> select ename,sal from emp order by sal desc limit 5;
±------±--------+
| ename | sal |
±------±--------+
| KING | 5000.00 |
| SCOTT | 3000.00 |
| FORD | 3000.00 |
| JONES | 2975.00 |
| BLAKE | 2850.00 |
±------±--------+
10、取得薪水最高的第六到第十名员工
select ename,sal from emp order by sal desc limit 5 ,5;
mysql> select ename,sal from emp order by sal desc limit 5 ,5;
±-------±--------+
| ename | sal |
±-------±--------+
| CLARK | 2450.00 |
| ALLEN | 1600.00 |
| TURNER | 1500.00 |
| MILLER | 1300.00 |
| MARTIN | 1250.00 |
±-------±--------+
5 rows in set (0.00 sec)
11、取得最后入职的5名员工
select ename,hiredate from emp order by hiredate desc limit 5 ;
±-------±-----------+
| ename | hiredate |
±-------±-----------+
| ADAMS | 1987-05-23 |
| SCOTT | 1987-04-19 |
| MILLER | 1982-01-23 |
| FORD | 1981-12-03 |
| JAMES | 1981-12-03 |
±-------±-----------+
12、取得每个薪水等级有多少员工
找出每个员工的薪水等级
select e.ename,s.grade from emp e join salgrade s on e.sal between s.losal and s.hisal;
±-------±------+
| ename | grade |
±-------±------+
| SMITH | 1 |
| ALLEN | 3 |
| WARD | 2 |
| JONES | 4 |
| MARTIN | 2 |
| BLAKE | 4 |
| CLARK | 4 |
| SCOTT | 4 |
| KING | 5 |
| TURNER | 3 |
| ADAMS | 1 |
| JAMES | 1 |
| FORD | 4 |
| MILLER | 2 |
±-------±------+
在上面的基础按照 grade 分组 用函数count计数
select s.grade,count(*) from emp e join salgrade s on e.sal between s.losal and s.hisal group by s.grade;
±------±---------+
| grade | count(*) |
±------±---------+
| 1 | 3 |
| 2 | 3 |
| 3 | 2 |
| 4 | 5 |
| 5 | 1 |
±------±---------+
13、面试题 —>85
有3个表S(学生表)，C（课程表），SC（学生选课表）
S（SNO，SNAME）代表（学号，姓名）
C（CNO，CNAME，CTEACHER）代表（课号，课名，教师）
SC（SNO，CNO，SCGRADE）代表（学号，课号，成绩）
问题：
1，找出没选过“黎明”老师的所有学生姓名。
2，列出2门以上（含2门）不及格学生姓名及平均成绩。
3，即学过1号课程又学过2号课所有学生的姓名。
请用标准SQL语言写出答案，方言也行（请说明是使用什么方言）。
CREATE TABLE SC
(
SNO VARCHAR(200),
CNO VARCHAR(200),
SCGRADE VARCHAR(200)
);
CREATE TABLE S
(
SNO VARCHAR(200 ),
SNAME VARCHAR(200)
);
CREATE TABLE C
(
CNO VARCHAR(200),
CNAME VARCHAR(200),
CTEACHER VARCHAR(200)
);
INSERT INTO C ( CNO, CNAME, CTEACHER ) VALUES ( ‘1’, ‘语文’, ‘张’);
INSERT INTO C ( CNO, CNAME, CTEACHER ) VALUES ( ‘2’, ‘政治’, ‘王’);
INSERT INTO C ( CNO, CNAME, CTEACHER ) VALUES ( ‘3’, ‘英语’, ‘李’);
INSERT INTO C ( CNO, CNAME, CTEACHER ) VALUES ( ‘4’, ‘数学’, ‘赵’);
INSERT INTO C ( CNO, CNAME, CTEACHER ) VALUES ( ‘5’, ‘物理’, ‘黎明’);
commit;
INSERT INTO S ( SNO, SNAME ) VALUES ( ‘1’, ‘学生1’);
INSERT INTO S ( SNO, SNAME ) VALUES ( ‘2’, ‘学生2’);
INSERT INTO S ( SNO, SNAME ) VALUES ( ‘3’, ‘学生3’);
INSERT INTO S ( SNO, SNAME ) VALUES ( ‘4’, ‘学生4’);
commit;
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘1’, ‘1’, ‘40’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘1’, ‘2’, ‘30’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘1’, ‘3’, ‘20’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘1’, ‘4’, ‘80’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘1’, ‘5’, ‘60’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘2’, ‘1’, ‘60’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘2’, ‘2’, ‘60’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘2’, ‘3’, ‘60’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘2’, ‘4’, ‘60’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘2’, ‘5’, ‘40’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘3’, ‘1’, ‘60’);
INSERT INTO SC ( SNO, CNO, SCGRADE ) VALUES ( ‘3’, ‘3’, ‘80’);
commit;
问题1.找出没选过“黎明”老师的所有学生姓名。
问题2:列出2门以上（含2门）不及格学生姓名及平均成绩。
问题3:即学过1号课程又学过2号课所有学生的姓名。
14、列出所有员工及领导的姓名
select a.ename ‘员工’ ,b.ename ‘领导’ from emp a left join emp b on a.mgr = b.empno;
±-------±------+
| 员工 | 领导 |
±-------±------+
| SMITH | FORD |
| ALLEN | BLAKE |
| WARD | BLAKE |
| JONES | KING |
| MARTIN | BLAKE |
| BLAKE | KING |
| CLARK | KING |
| SCOTT | JONES |
| KING | NULL |
| TURNER | BLAKE |
| ADAMS | SCOTT |
| JAMES | BLAKE |
| FORD | JONES |
| MILLER | CLARK |
±-------±------+
15、列出受雇日期早于其直接上级的所有员工的编号,姓名,部门名称
emp a 员工 emp b 领导 a hiredate < b hiredate
select a.ename ‘员工’,a.hiredate,b.ename ‘领导’,b.hiredate,d.dname from emp a join emp b on a.mgr = b.empno join dept d on a.deptno = d.deptno where a.hiredate<b.hiredate;
±------±-----------±------±-----------±-----------+
| 员工 | hiredate | 领导 | hiredate | dname |
±------±-----------±------±-----------±-----------+
| CLARK | 1981-06-09 | KING | 1981-11-17 | ACCOUNTING |
| SMITH | 1980-12-17 | FORD | 1981-12-03 | RESEARCH |
| JONES | 1981-04-02 | KING | 1981-11-17 | RESEARCH |
| ALLEN | 1981-02-20 | BLAKE | 1981-05-01 | SALES |
| WARD | 1981-02-22 | BLAKE | 1981-05-01 | SALES |
| BLAKE | 1981-05-01 | KING | 1981-11-17 | SALES |
±------±-----------±------±-----------±-----------+
16、列出部门名称和这些部门的员工信息,同时列出那些没有员工的部门
select e., d. from emp e right join dept d on e.deptno = d.deptno;
±------±-------±----------±-----±-----------±--------±--------±-------±-------±-----------±---------+
| EMPNO | ENAME | JOB | MGR | HIREDATE | SAL | COMM | DEPTNO | DEPTNO | DNAME | LOC |
±------±-------±----------±-----±-----------±--------±--------±-------±-------±-----------±---------+
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 | 2450.00 | NULL | 10 | 10 | ACCOUNTING | NEW YORK |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 | 5000.00 | NULL | 10 | 10 | ACCOUNTING | NEW YORK |
| 7934 | MILLER | CLERK | 7782 | 1982-01-23 | 1300.00 | NULL | 10 | 10 | ACCOUNTING | NEW YORK |
| 7369 | SMITH | CLERK | 7902 | 1980-12-17 | 800.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 | 2975.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 | 3000.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 7876 | ADAMS | CLERK | 7788 | 1987-05-23 | 1100.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 | 3000.00 | NULL | 20 | 20 | RESEARCH | DALLAS |
| 7499 | ALLEN | SALESMAN | 7698 | 1981-02-20 | 1600.00 | 300.00 | 30 | 30 | SALES | CHICAGO |
| 7521 | WARD | SALESMAN | 7698 | 1981-02-22 | 1250.00 | 500.00 | 30 | 30 | SALES | CHICAGO |
| 7654 | MARTIN | SALESMAN | 7698 | 1981-09-28 | 1250.00 | 1400.00 | 30 | 30 | SALES | CHICAGO |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 | 2850.00 | NULL | 30 | 30 | SALES | CHICAGO |
| 7844 | TURNER | SALESMAN | 7698 | 1981-09-08 | 1500.00 | 0.00 | 30 | 30 | SALES | CHICAGO |
| 7900 | JAMES | CLERK | 7698 | 1981-12-03 | 950.00 | NULL | 30 | 30 | SALES | CHICAGO |
| NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | 40 | OPERATIONS | BOSTON |
±------±-------±----------±-----±-----------±--------±--------±-------±-------±-----------±---------+
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17、列出至少有5个员工的所有部门
按照部门编号分组 计数 筛选出大于等于5的的部门
select deptno from emp group by deptno having count(*)>=5 ;
±-------+
| deptno |
±-------+
| 20 |
| 30 |
±-------+
18、列出薪金比"SMITH"多的所有员工信息.
select * from emp where sal>(select sal from emp where ename = ‘smith’);
±------±-------±----------±-----±-----------±--------±--------±-------+
| EMPNO | ENAME | JOB | MGR | HIREDATE | SAL | COMM | DEPTNO |
±------±-------±----------±-----±-----------±--------±--------±-------+
| 7499 | ALLEN | SALESMAN | 7698 | 1981-02-20 | 1600.00 | 300.00 | 30 |
| 7521 | WARD | SALESMAN | 7698 | 1981-02-22 | 1250.00 | 500.00 | 30 |
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 | 2975.00 | NULL | 20 |
| 7654 | MARTIN | SALESMAN | 7698 | 1981-09-28 | 1250.00 | 1400.00 | 30 |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 | 2850.00 | NULL | 30 |
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 | 2450.00 | NULL | 10 |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 | 3000.00 | NULL | 20 |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 | 5000.00 | NULL | 10 |
| 7844 | TURNER | SALESMAN | 7698 | 1981-09-08 | 1500.00 | 0.00 | 30 |
| 7876 | ADAMS | CLERK | 7788 | 1987-05-23 | 1100.00 | NULL | 20 |
| 7900 | JAMES | CLERK | 7698 | 1981-12-03 | 950.00 | NULL | 30 |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 | 3000.00 | NULL | 20 |
| 7934 | MILLER | CLERK | 7782 | 1982-01-23 | 1300.00 | NULL | 10 |
±------±-------±----------±-----±-----------±--------±--------±-------+
19、列出所有"CLERK"(办事员)的姓名及其部门名称,部门的人数
select ename,job from emp where job = ‘clerk’;
±-------±------+
| ename | job |
±-------±------+
| SMITH | CLERK |
| ADAMS | CLERK |
| JAMES | CLERK |
| MILLER | CLERK |
±-------±------+
select e.ename,e.job,d.dname,e.deptno from emp e join dept d on e.deptno = d.deptno where job = ‘clerk’;
±-------±------±-----------±-------+
| ename | job | dname | deptno |
±-------±------±-----------±-------+
| MILLER | CLERK | ACCOUNTING | 10 |
| SMITH | CLERK | RESEARCH | 20 |
| ADAMS | CLERK | RESEARCH | 20 |
| JAMES | CLERK | SALES | 30 |
±-------±------±-----------±-------+
select deptno,count(*) as deptcount from emp group by deptno;
±-------±----------+
| deptno | deptcount |
±-------±----------+
| 10 | 3 |
| 20 | 5 |
| 30 | 6 |
±-------±----------+
select t1.,t2.deptcount from (select e.ename,e.job,d.dname,e.deptno from emp e join dept d on e.deptno = d.deptno where job = ‘clerk’) t1 join (select deptno,count() as deptcount from emp group by deptno) t2 on t1.deptno = t2.deptno;
±-------±------±-----------±-------±----------+
| ename | job | dname | deptno | deptcount |
±-------±------±-----------±-------±----------+
| MILLER | CLERK | ACCOUNTING | 10 | 3 |
| SMITH | CLERK | RESEARCH | 20 | 5 |
| ADAMS | CLERK | RESEARCH | 20 | 5 |
| JAMES | CLERK | SALES | 30 | 6 |
±-------±------±-----------±-------±----------+
20、列出最低薪金大于1500的各种工作及从事此工作的全部雇员人数
select job,count(*) from emp group by job having min(sal)>1500;
±----------±---------+
| job | count(*) |
±----------±---------+
| ANALYST | 2 |
| MANAGER | 3 |
| PRESIDENT | 1 |
±----------±---------+
21、列出在部门"SALES"<销售部>工作的员工的姓名,假定不知道销售部的部门编号
select deptno from dept where dname = ‘sales’;
±-------+
| deptno |
±-------+
| 30 |
±-------+
select ename from emp where deptno = (select deptno from dept where dname = ‘sales’);
±-------+
| ename |
±-------+
| ALLEN |
| WARD |
| MARTIN |
| BLAKE |
| TURNER |
| JAMES |
±-------+
22、列出薪金高于公司平均薪金的所有员工,所在部门,上级领导,雇员的工资等级
mysql> select avg(sal) from emp;
±------------+
| avg(sal) |
±------------+
| 2073.214286 |
±------------+
select e.ename ‘员工’,d.dname,l.ename ‘领导’, s.grade
from emp e
join dept d
on e.deptno = d.deptno
left join emp l
on e.mgr = l.empno
join salgrade s
on e.sal between s.losal and s.hisal
where e.sal>( select avg(sal) from emp);
±------±-----------±------±------+
| 员工 | dname | 领导 | grade |
±------±-----------±------±------+
| JONES | RESEARCH | KING | 4 |
| BLAKE | SALES | KING | 4 |
| CLARK | ACCOUNTING | KING | 4 |
| SCOTT | RESEARCH | JONES | 4 |
| KING | ACCOUNTING | NULL | 5 |
| FORD | RESEARCH | JONES | 4 |
±------±-----------±------±------+
23、列出与"SCOTT"从事相同工作的所有员工及部门名称
select job from emp where ename = ‘scott’;
±--------+
| job |
±--------+
| ANALYST |
±--------+
select e.ename,d.dname,e.job
from emp e
join dept d
on e.deptno = d.deptno
where job = (select job from emp where ename = ‘scott’)
and e.ename <> ‘scott’;
±------±---------±--------+
| ename | dname | job |
±------±---------±--------+
| FORD | RESEARCH | ANALYST |
±------±---------±--------+
24、列出薪金等于部门30中员工的薪金的其他员工的姓名和薪金
select sal from emp where deptno = 30;
±--------+
| sal |
±--------+
| 1600.00 |
| 1250.00 |
| 1250.00 |
| 2850.00 |
| 1500.00 |
| 950.00 |
±--------+
select ename,sal from emp where sal in (select sal from emp where deptno = 30) and deptno <> 30;
Empty set (0.00 sec)
25、列出薪金高于在部门30工作的所有员工的薪金的员工姓名和薪金.部门名称
select max(sal) from emp where deptno = 30 ;
±---------+
| max(sal) |
±---------+
| 2850.00 |
±---------+
select e.ename,e.sal,d.dname from emp e join dept d on e.deptno= d.deptno where e.sal > (select max(sal) from emp where deptno = 30) ;
±------±--------±-----------+
| ename | sal | dname |
±------±--------±-----------+
| KING | 5000.00 | ACCOUNTING |
| JONES | 2975.00 | RESEARCH |
| SCOTT | 3000.00 | RESEARCH |
| FORD | 3000.00 | RESEARCH |
±------±--------±-----------+
26、列出在每个部门工作的员工数量,平均工资和平均服务期限
select avg(sal) ,count(*),avg(timestampdiff(year,hiredate,now())) from emp group by deptno;
±------------±---------±----------------------------------------+
| avg(sal) | count(*) | avg(timestampdiff(year,hiredate,now())) |
±------------±---------±----------------------------------------+
| 2916.666667 | 3 | 39.3333 |
| 2175.000000 | 5 | 37.4000 |
| 1566.666667 | 6 | 39.5000 |
±------------±---------±----------------------------------------+
27、列出所有员工的姓名、部门名称和工资
select e.ename,d.dname,e.sal from emp e join dept d on e.deptno =d.deptno;
±-------±-----------±--------+
| ename | dname | sal |
±-------±-----------±--------+
| CLARK | ACCOUNTING | 2450.00 |
| KING | ACCOUNTING | 5000.00 |
| MILLER | ACCOUNTING | 1300.00 |
| SMITH | RESEARCH | 800.00 |
| JONES | RESEARCH | 2975.00 |
| SCOTT | RESEARCH | 3000.00 |
| ADAMS | RESEARCH | 1100.00 |
| FORD | RESEARCH | 3000.00 |
| ALLEN | SALES | 1600.00 |
| WARD | SALES | 1250.00 |
| MARTIN | SALES | 1250.00 |
| BLAKE | SALES | 2850.00 |
| TURNER | SALES | 1500.00 |
| JAMES | SALES | 950.00 |
±-------±-----------±--------+
28、列出所有部门的详细信息和人数
select deptno,count(*)as deptcount from emp group by deptno;
±-------±----------+
| deptno | deptcount |
±-------±----------+
| 10 | 3 |
| 20 | 5 |
| 30 | 6 |
±-------±----------+
select d.,t.deptcount from dept d left join (select deptno,count()as deptcount from emp group by deptno) t on d.deptno = t.deptno;
±-------±-----------±---------±----------+
| DEPTNO | DNAME | LOC | deptcount |
±-------±-----------±---------±----------+
| 10 | ACCOUNTING | NEW YORK | 3 |
| 20 | RESEARCH | DALLAS | 5 |
| 30 | SALES | CHICAGO | 6 |
| 40 | OPERATIONS | BOSTON | NULL |
±-------±-----------±---------±----------+
select d.deptno,d.dname,d.loc,count(e.ename)
from emp e right join dept d
on e.deptno = d.deptno
group by d.deptno,d.dname,d.loc;
±-------±-----------±---------±---------------+
| deptno | dname | loc | count(e.ename) |
±-------±-----------±---------±---------------+
| 10 | ACCOUNTING | NEW YORK | 3 |
| 20 | RESEARCH | DALLAS | 5 |
| 30 | SALES | CHICAGO | 6 |
| 40 | OPERATIONS | BOSTON | 0 |
±-------±-----------±---------±---------------+
29、列出各种工作的最低工资及从事此工作的雇员姓名
select job,min(sal) as minsal from emp group by job;
±----------±--------+
| job | minsal |
±----------±--------+
| ANALYST | 3000.00 |
| CLERK | 800.00 |
| MANAGER | 2450.00 |
| PRESIDENT | 5000.00 |
| SALESMAN | 1250.00 |
±----------±--------+
emp e 跟上面的t连接
select e.ename,t.* from emp e join (select job,min(sal) as minsal from emp group by job) t on e.job = t.job and e.sal = t.minsal ;
±-------±----------±--------+
| ename | job | minsal |
±-------±----------±--------+
| SMITH | CLERK | 800.00 |
| WARD | SALESMAN | 1250.00 |
| MARTIN | SALESMAN | 1250.00 |
| CLARK | MANAGER | 2450.00 |
| SCOTT | ANALYST | 3000.00 |
| KING | PRESIDENT | 5000.00 |
| FORD | ANALYST | 3000.00 |
±-------±----------±--------+
30、列出各个部门的MANAGER(领导)的最低薪金
select ename,deptno,min(sal) as minsal from emp where job = ‘manager’ group by deptno ;
±------±-------±--------+
| ename | deptno | minsal |
±------±-------±--------+
| CLARK | 10 | 2450.00 |
| JONES | 20 | 2975.00 |
| BLAKE | 30 | 2850.00 |
±------±-------±--------+
31、列出所有员工的年工资,按年薪从低到高排序
select ename,(sal + ifnull(comm,0) )*12 as yearsal from emp order by yearsal;
±-------±---------+
| ename | yearsal |
±-------±---------+
| SMITH | 9600.00 |
| JAMES | 11400.00 |
| ADAMS | 13200.00 |
| MILLER | 15600.00 |
| TURNER | 18000.00 |
| WARD | 21000.00 |
| ALLEN | 22800.00 |
| CLARK | 29400.00 |
| MARTIN | 31800.00 |
| BLAKE | 34200.00 |
| JONES | 35700.00 |
| FORD | 36000.00 |
| SCOTT | 36000.00 |
| KING | 60000.00 |
±-------±---------+
32、求出员工领导的薪水超过3000的员工名称与领导名称
select e.ename ‘员工’,t.ename ‘领导’ from emp e join emp t on e.mgr = t.empno where t.sal>3000;
±------±-----+
| 员工 | 领导 |
±------±-----+
| JONES | KING |
| BLAKE | KING |
| CLARK | KING |
±------±-----+
33、求出部门名称中,带’S’字符的部门员工的工资合计、部门人数
select d.deptno,d.dname,d.loc,count(ename),ifnull (sum(e.sal),0) as sumsal
from emp e right join dept d
on e.deptno = d.deptno where d.dname like ‘%S%’
group by d.deptno,d.dname,d.loc;
±-------±-----------±--------±-------------±---------+
| deptno | dname | loc | count(ename) | sumsal |
±-------±-----------±--------±-------------±---------+
| 20 | RESEARCH | DALLAS | 5 | 10875.00 |
| 30 | SALES | CHICAGO | 6 | 9400.00 |
| 40 | OPERATIONS | BOSTON | 0 | 0.00 |
±-------±-----------±--------±-------------±---------+
34、给任职日期超过30年的员工加薪10%
update emp set sal = sal *1.1 where timestampdiff(year,hiredate,now())>30;
mysql> select * from emp;
±------±-------±----------±-----±-----------±--------±--------±-------+
| EMPNO | ENAME | JOB | MGR | HIREDATE | SAL | COMM | DEPTNO |
±------±-------±----------±-----±-----------±--------±--------±-------+
| 7369 | SMITH | CLERK | 7902 | 1980-12-17 | 880.00 | NULL | 20 |
| 7499 | ALLEN | SALESMAN | 7698 | 1981-02-20 | 1760.00 | 300.00 | 30 |
| 7521 | WARD | SALESMAN | 7698 | 1981-02-22 | 1375.00 | 500.00 | 30 |
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 | 3272.50 | NULL | 20 |
| 7654 | MARTIN | SALESMAN | 7698 | 1981-09-28 | 1375.00 | 1400.00 | 30 |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 | 3135.00 | NULL | 30 |
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 | 2695.00 | NULL | 10 |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 | 3300.00 | NULL | 20 |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 | 5500.00 | NULL | 10 |
| 7844 | TURNER | SALESMAN | 7698 | 1981-09-08 | 1650.00 | 0.00 | 30 |
| 7876 | ADAMS | CLERK | 7788 | 1987-05-23 | 1210.00 | NULL | 20 |
| 7900 | JAMES | CLERK | 7698 | 1981-12-03 | 1045.00 | NULL | 30 |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 | 3300.00 | NULL | 20 |
| 7934 | MILLER | CLERK | 7782 | 1982-01-23 | 1430.00 | NULL | 10 |
±------±-------±----------±-----±-----------±--------±--------±-------+