题目大意:给n个0~m之间的数,如果是0,那么0可以变为任意的一个1~m之间的一个数。从中选出若干个数,使构成一个连续的序列。问能构成的最长序列的长度为多少?
题目分析:枚举连续序列的起点,二分枚举二分序列的终点。
代码如下;
# include<iostream>
# include<cstdio>
# include<queue>
# include<vector>
# include<list>
# include<map>
# include<set>
# include<cstdlib>
# include<string>
# include<cstring>
# include<algorithm>
using namespace std;
# define LL long long const int N=1000;
const int INF=1<<30;
const LL oo=1e15;
const double eps=1e-20; int n,m;
int sum[N*100+5]; int main()
{
int T;
scanf("%d",&T);
while(T--)
{
scanf("%d%d",&n,&m);
memset(sum,0,sizeof(sum));
int a,k=0;
for(int i=0;i<n;++i){
scanf("%d",&a);
if(a) sum[a]=1;
else ++k;
}
for(int i=1;i<=m;++i)
sum[i]+=sum[i-1];
int ans=0;
for(int i=1;i<=m;++i){
int l=i,r=m;
while(l<=r){
int x=(l+r)>>1;
if(sum[x]-sum[i-1]+k>=x-i+1){
ans=max(ans,x-i+1);
l=x+1;
}else{
r=x-1;
}
}
}
printf("%d\n",ans);
}
return 0;
}