1 #include <iostream>
 2 const int N = 54;
 3 using namespace std;
 4 int main()
 5 {
 6     char type[5] = { ‘S‘,‘H‘,‘C‘,‘D‘,‘J‘ };//0-12:S, 13-25:H, 26-38:C, 39-51:D, 52-53:J
 7     int k,res[N],origin[N];//第i个位置的数据应该放到下标为origin[i]的位置，假如origin[0]为36，则第36个位置（下标为36）应该放置第0个位置的数据
 8     cin >> k;
 9     for (int i = 0; i < N; ++i) origin[i] = i;
10     int order[N];
11     for (int i = 0; i < N; ++i) cin >> order[i];
12     for (int i = 0; i < k; ++i)
13     {
14         for (int j = 0; j < N; ++j)
15             res[order[j]-1] = origin[j];//比如order[0]是30，则把origin[0]放到res[29]
16         for (int z = 0; z < N; ++z)//下一次循环，将res的结果作为origin的新结果
17             origin[z] = res[z];
18     }
19     for (int i = 0; i < N; ++i)
20     {
21         int t = res[i];
22         cout << type[t / 13] << t % 13+1;
23         if (i != N-1)
24             cout << ‘ ‘;
25     }
26     return 0;
27 }