uva 11573(bfs)

题意:给一个方阵表示一个湖每个格子代表那个位置的风向,顺风走不要花费否则花费为1。给你起点重点问你最小花费是多少?

思路:这道题写的四不像,先spfa写了一下T,然后bfs又T。接着加了个优先队列就过了。。。主要就是类似于spfa dis数组记录到那点的最小花费。然后只要能更新就入队。

代码如下:

uva 11573(bfs)
 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstdlib>
 4 #include <cmath>
 5 #include <cstring>
 6 #include <algorithm>
 7 #include <queue>
 8 #include <stack>
 9 #include <vector>
10 #include <set>
11 #include <map>
12 #define PB(a) push_back(a)
13 
14 using namespace std;
15 
16 typedef long long ll;
17 typedef pair<int ,int> pii;
18 typedef pair<unsigned int, unsigned int> puu;
19 typedef pair<int ,double> pid;
20 typedef pair<ll, int> pli;
21 typedef pair<int, ll> pil;
22 
23 const int INF = 0x3f3f3f3f;
24 const double eps = 1e-6;
25 const int LEN = 1002;
26 int Map[LEN][LEN], n, m, dis[LEN][LEN];
27 int xx[] = {-1,-1, 0, 1, 1, 1, 0,-1};
28 int yy[] = { 0, 1, 1, 1, 0,-1,-1,-1};
29 struct P {int x, y, st;};
30 struct cmp
31 {
32     bool operator() (P a, P b){return a.st>b.st;}
33 };
34 
35 P temp;
36 
37 int bfs(int x, int y, int ex, int ey)
38 {
39     temp.x = x;temp.y = y;temp.st = 0;
40     priority_queue<P, vector<P>, cmp> q;
41     int ret = INF;
42     q.push(temp);
43     register int tx, ty, i;
44     memset(dis, 0x3f, sizeof dis);
45     dis[x][y] = 0;
46     while(!q.empty()){
47         P vex = q.top();q.pop();
48         if(vex.x==ex && vex.y==ey) {return vex.st;}
49         for(i=0; i<8; i++){
50             tx = vex.x+xx[i];
51             ty = vex.y+yy[i];
52             temp.st = vex.st+(i==Map[vex.x][vex.y]?0:1);
53             if(tx>=0 && tx<n && ty>=0 && ty<m && dis[tx][ty] > temp.st){
54                 temp.x = tx;temp.y = ty;
55                 dis[tx][ty] = temp.st;
56                 q.push(temp);
57             }
58         }
59     }
60 }
61 
62 void read(int &ret)
63 {
64     char c;
65     while((c = getchar())<0 || c>9);
66     ret = 0;
67     while(c>=0 && c<=9){
68         ret = ret*10+(c-0);
69         c = getchar();
70     }
71 }
72 
73 int main()
74 {
75 //    freopen("in.txt", "r", stdin);
76 
77     int q, sx, sy, ex, ey, ans;
78     while(scanf("%d%d", &n, &m)!=EOF){
79         getchar();
80         for(int i=0; i<n; i++){
81             for(int j=0; j<m; j++){
82                 Map[i][j] = getchar()-0;
83             }
84             getchar();
85         }
86         read(q);
87         for(int i=0; i<q; i++){
88             read(sx);read(sy);read(ex);read(ey);
89             ans = bfs(sx-1, sy-1, ex-1, ey-1);
90             printf("%d\n", ans);
91         }
92     }
93     return 0;
94 }
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uva 11573(bfs)

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