格式化字符串为时间学习总结

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
package main
 
import (
    "fmt"
    "time"
)
 
func main() {
    test, err := time.Parse("2006-01-02", "2013-01-12")
    if err != nil {
        panic(err)
    }
 
    fmt.Println(test)
}
[ `run` | done: 4.533945ms ]
2013-01-12 00:00:00 +0000 UTC

其中time.parse格式改变后,未发生变化

1
test, err := time.Parse("2006/01/02", "2013/01/12")
[ `run` | done: 1.499388ms ]
2013-01-12 00:00:00 +0000 UTC

再换,结果未变:

1
test, err := time.Parse("01/02/2006", "01/12/2013")
[ `run` | done: 1.471152ms ]
2013-01-12 00:00:00 +0000 UTC

截取取小时:

1
test, err := time.Parse("2006-01-02 15", "2013-05-13 13")

截取到分钟:

1
test, err := time.Parse("2006-01-02 15:04", "2013-05-13 10:30")
[ `run` | done: 1.414665ms ]
2013-05-13 10:30:00 +0000 UTC

截取到秒:

 
1
test, err := time.Parse("2006-01-02 15:04:05", "2013-05-13 10:30:03")
[ `run` | done: 1.554238ms ]
2013-05-13 10:30:03 +0000 UTC

 

随着截取位置的不同,通过补零设置

格式化字符串为时间学习总结

上一篇:maven2介绍(转)


下一篇:SQL语句(十六)实现集合运算、对数据修改、数据表复制