Drools版本：6.3.0.Final

POJO：

public class Person {
    private Integer age;
    private Integer childrens;
    private String name;
    private String address;
    (...) 
}

DSL文件：

[condition][]and=&&
[condition][]or=||
[condition][]is less than or equal to=<=
[condition][]is less than=<
[condition][]is greater than or equal to=>=
[condition][]is greater than=>
[condition][]is equal to===
[condition][]There is a [Pp]erson with=$person:Person()
[condition][].{field:\w*}  {operator}  {value:\d*}={field}  {operator}  {value}
(...)

DSRL文件：

package <package>;

import <import class>.*

global org.slf4j.Logger logger;

expander <class>.dsl;

rule "R1"
    when
        There is a person with
        .age is greater than 10 or .chidldrens is less than 2 and .name is  equal to "<name>"
    then
        (...)
end 

rule "R2"
    when
        There is a person with
        (.age is greater than 10 or .childrens is less than 2) and .name is equal to "<name>"
    then
        (...)
end 

DRL(来自R1)：

(...)
rule "R1"
        when
            $person:Person(age > 10 || childrens < 2 && name = "<name>")
        then
            (...)
    end 
(...)

DRL(来自R2)：未生成规则.

如果我删除它的括号,但是使用括号,则无法正确生成DRL文件.所以只有R2规则正在运行,但我的目标是R1规则.

任何的想法？

解决方法:

我想我发现了一个可能的解决方案：

DSL文件(替换为这个新条件)：

[condition][]There is a [Pp]erson that {constraints}=$person:Person({constraints})
[condition][]{field:\w*}\s+{operator}\s+{value:\s*}={field}  {operator}  {value}

DSRL(定义从第一行开始的约束)：

(...)
There is a person that ((age is greater than 10 or chidldrens is less than 2) and name is equal to "<name>")
(...)

DRL(生成)：

(...)
$person:Person((age > 10 || childrens < 2) && name == "name")
(...)

使用这个新的DSL定义括号,它正在按预期工作.你怎么看@laune？