LeetCode OJ:Edit Distance

Edit Distance

 

Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.)

You have the following 3 operations permitted on a word:

a) Insert a character
b) Delete a character
c) Replace a character

算法思想:动态规划

D(i,j)=min { D(i-1, j) +1, D(i, j-1) +1 , D(i-1, j-1) + s1[i]==s2[j] ? 0 : 1}

class Solution {
public:
    int minDistance(string word1, string word2) {
        
        int m=word1.size();
        int n=word2.size();
        vector<vector<int>> dis(m+1);
        for(int i=0;i<=m;i++)dis[i].assign(n+1,INT_MAX);
        
        dis[0][0]=0;
        for(int i=0;i<=m;i++)
        for(int j=0;j<=n;j++){
            if(i>0) dis[i][j] = min(dis[i][j],dis[i-1][j]+1); //delete  
            if(j>0) dis[i][j] = min(dis[i][j],dis[i][j-1]+1);//insert  
  
            //substitute  
            if(i>0&&j>0)  
            {  
                if(word1[i-1]!=word2[j-1])  
                    dis[i][j] = min(dis[i][j],dis[i-1][j-1]+1);  
                else  
                    dis[i][j] = min(dis[i][j],dis[i-1][j-1]);  
            }  
        }
        return dis[m][n];
    }
};


LeetCode OJ:Edit Distance

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