2 seconds
256 megabytes
standard input
standard output
Ford Prefect got a job as a web developer for a small company that makes towels. His current work task is to create a search engine for the website of the company. During the development process, he needs to write a subroutine for comparing strings S and T of
equal length to be "similar". After a brief search on the Internet, he learned about the Hamming distance between two strings S and T of
the same length, which is defined as the number of positions in which S and T have
different characters. For example, the Hamming distance between words "permanent" and "pergament"
is two, as these words differ in the fourth and sixth letters.
Moreover, as he was searching for information, he also noticed that modern search engines have powerful mechanisms to correct errors in the request to improve the quality of search. Ford doesn't know much about human beings, so he assumed that the most common
mistake in a request is swapping two arbitrary letters of the string (not necessarily adjacent). Now he wants to write a function that determines which two letters should be swapped in string S,
so that the Hamming distance between a new string S and string T would
be as small as possible, or otherwise, determine that such a replacement cannot reduce the distance between the strings.
Help him do this!
The first line contains integer n (1 ≤ n ≤ 200 000)
— the length of strings S and T.
The second line contains string S.
The third line contains string T.
Each of the lines only contains lowercase Latin letters.
In the first line, print number x — the minimum possible Hamming distance between strings S and T if
you swap at most one pair of letters in S.
In the second line, either print the indexes i and j (1 ≤ i, j ≤ n, i ≠ j),
if reaching the minimum possible distance is possible by swapping letters on positions i and j,
or print "-1 -1", if it is not necessary to swap characters.
If there are multiple possible answers, print any of them.
9
pergament
permanent
1
4 6
6
wookie
cookie
1
-1 -1
4
petr
egor
2
1 2
6
double
bundle
2
4 1
In the second test it is acceptable to print i = 2, j = 3.
题意：交换S或者T中的两个字符。使得两串的差异度最小。有三种情况，一种是交换后正好两个位置都相应同样，一种是交换后仅仅有一个位置同样，还有就是交换也不能满足相应同样。
#include <iostream>
#include <stdio.h>
#include <string>
#include <cstring>
#define N 2222
using namespace std; char s[200009],t[200009];
int n;
int a[N][N]; int main()
{
while(~scanf("%d",&n))
{
scanf("%s %s",s,t); int num=0;
memset(a,0,sizeof a); for(int i=0;i<n;i++)
if(s[i]!=t[i])
{
int x=s[i]-'a';
int y=t[i]-'a';
num++;
a[x][y]=i+1;
} for(int i=0;i<26;i++)//交换后两位置都相应同样了
for(int j=0;j<26;j++)
if(a[i][j] && a[j][i])
{
cout<<num-2<<endl;
cout<<a[i][j]<<" "<<a[j][i]<<endl;
return 0;
} for(int i=0;i<26;i++)//交换后仅仅有一个位置相应同样
for(int j=0;j<26;j++)
if(a[i][j])
{
for(int k=0;k<26;k++)
if(a[j][k])
{
cout<<num-1<<endl;
cout<<a[i][j]<<" "<<a[j][k]<<endl;
return 0;
}
} cout<<num<<endl;
cout<<-1<<" "<<-1<<endl;//无法通过交换降低差异度 }
return 0;
}