#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int N = 20;
const int M = 3010;
int n, m;
LL v[N];
LL f[M];
int main() {
cin >> n >> m;
//base case
f[0] = 1;
for (int i = 1; i <= n; i++) {
cin >> v[i];
for (int j = v[i]; j <= m; j++)
f[j] += f[j - v[i]];
}
//一个整数,代表选择方案种数
printf("%lld", f[m]);
return 0;
}