JSON与Java对象的互相转换

JSON与Java对象的互相转换

  • 例一(单个对象进行赋值):

      @RequestMapping("test1.do")
    @ResponseBody
    public JSONObject test1(HttpServletRequest request, HttpServletResponse response) {
    JSONObject jsonObject = new JSONObject();
    jsonObject.put("key1", "value1");
    jsonObject.put("key2", "value2");
    jsonObject.put("key3", "value3");
    return jsonObject;
    }
  • 例二(多个对象进行转换):

      @RequestMapping("TestListQrcode.do")
    @ResponseBody
    public JSONObject TestListQrcode(HttpServletRequest request, HttpServletResponse response)
    throws Exception {
    //String user_phone = request.getParameter("user_phone");
    String user_phone ="13652458975"; Qrcode qrcode = new Qrcode();
    qrcode.setUser_phone(user_phone);
    qrcode.setQrcode_type("普通型");
    List<Qrcode> list = qrcodeService.selectQrcodeList(qrcode); //创建json集合
    //用的包:import net.sf.json.JSONArray;
    JSONArray jsonArray = JSONArray.fromObject(list);
    System.out.println(jsonArray.toString());
    JSONObject jsonObject = new JSONObject();
    jsonObject.put("code", 1); jsonObject.put("data", jsonArray.toString());
    return jsonObject;
    }
  • 例三(字符串的拼接,我只在servlet中用过):

      String value1 = "1";
    int value2 = count-1;
    System.out.println("给前面传的count:"+value2);
    String photo_file = par[0] + "/" + par[1] + "/images";
    //进行拼凑json字符串
    String jsonStr =
    "{" + '"'+ "success" + '"' +":" + '"' + value1 + '"' + ","
    + '"' + "count" + '"' +":" + '"' + value2 + '"' + ","
    + '"' + "photo_file" + '"' +":" + '"' + photo_file + '"'
    +"}" ;
    PrintWriter out =null ;
    out =response.getWriter() ;
    out.write(jsonStr);
    out.close();
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