import org.junit.Test; public class AllSort { public void permutation(char[] buf, int start, int end) { if (start == end) {// 当只要求对数组中一个字母进行全排列时,只要就按该数组输出即可 for (int i = 0; i <= end; i++) { System.out.print(buf[i]); } System.out.println(); } else {// 多个字母全排列 for (int i = start; i <= end; i++) { char temp = buf[start];// 交换数组第一个元素与后续的元素 buf[start] = buf[i]; buf[i] = temp; permutation(buf, start + 1, end);// 后续元素递归全排列 temp = buf[start];// 将交换后的数组还原 buf[start] = buf[i]; buf[i] = temp; } } } @Test public void testPermutation() throws Exception { char[] buf = new char[] { ‘a‘, ‘b‘, ‘c‘ }; permutation(buf, 0, 2); } }
运行测试,输出结果:
abc
acb
bac
bca
cba
cab