1.只要输出结果
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double x1 = 0.026 ;
System.out.println(String.format( "%.2f" , x1));
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2.数据转换
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//方案一: get_double = ( double )(Math.round(result_value* 100 )/ 100.0 )
//方案二: DecimalFormat df = new DecimalFormat( "#.##" );
get_double = Double.ParseDouble(df.format(result_value)); //方案三: get_double = Double.ParseDouble(String.format( "%.2f" ,result_value));
//方案四: BigDecimal bd = new BigDecimalresult_value();
BigDecimal bd2 = bd.setScale( 2 ,BigDecimal .ROUND_HALF_UP);
get_double = Double.ParseDouble(bd2.ToString()); |
3.只保留两位小数(不含四舍五入)
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double d = 13.4324 ;
d=(( int )(d* 100 ))/ 100 ;
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本文转自 glblong 51CTO博客,原文链接:http://blog.51cto.com/glblong/1312340,如需转载请自行联系原作者