用一个列表来确定for循环的范围
>>> x = [0,1,2,3,4]
>>> for i in x:
print i, 0 1 2 3 4
循环一个字符串
>>> x = 'python'
>>> for i in x:
print i, p y t h o n
元组for循环
>>> x = [('http','https'),('java','python')]
>>> for (a,b) in x:
print (a,b)
('http', 'https')
('java', 'python')
迭代器
# 文件迭代器，读取文件的最佳实践
>>> for line in open('test.txt'):
print line.upper() HELLO,WORD! # 字典迭代器
>>> testDict = {'name':'ethon','aender':'male'}
>>> for key in testDict:
print key + ':' + testDict[key] aender:male
name:ethon
迭代协议：有一些函数可以在支持迭代协议的对象上运行
>>> testList = [9,8,7,6,5]
>>> print sorted(testList)
[5, 6, 7, 8, 9]
>>> print sum(testList)
35
>>> print any(testList)
True
>>> print list(open('test.txt'))
['Hello,word!']
>>> print tuple(open('test.txt'))
('Hello,word!',)
# 元组、列表的构造函数以及join都可以对支持迭代协议的对象操作
>>> print ('--').join(open('test.txt'))
Hello,word!
使用range函数来产生循环的范围
>>> for i in range(5):
print str(i)+ 'is the current value' 0 is the current value
1 is the current value
2 is the current value
3 is the current value
4 is the current value
zip拉链：使用zip函数可以把两个列表合并起来，成为一个元组的列表。
>>> L1 = [1,3,5,7]
>>> L2 = [2,4,6,8]
>>> print zip(L1,L2)
[(1, 2), (3, 4), (5, 6), (7, 8)]
>>> for (a,b) in zip(L1,L2):
print (a,b) (1, 2)
(3, 4)
(5, 6)
(7, 8)
可变嵌套循环
ns = int(raw_input("How many lines of starts do you want? "))
st = int(raw_input("How many start do you want? "))
for line in range(0,ns): # 外循环
for star in range(0,st): # 内循环
print "*",
print
-------------------------------------------
How many lines of starts do you want? 3
How many start do you want? 5
* * * * *
* * * * *
* * * * *