以下脚本执行它应该做的事情,也就是说,它对“向左箭头”和“向右箭头”键做出反应.但是,由于键码冲突,它也会对单引号做出反应.这使得无法将该字符输入到输入字段中.可以做些什么吗？
<script type="text/javascript">
onl oad = function(){
document.onkeypress=function(e){
if(window.event) e=window.event;
var keycode=(e.keyCode)?e.keyCode:e.which;
switch(keycode){
case 37: window.location.href='set.jsp?index=5';
break;
case 39: window.location.href='set.jsp?index=7';
break;
}
}
}
</script>
解决方法:
当用户按下单引号键时,e.keyCode属性为零,e.which属性为39.执行String.fromCharCode(39)返回单引号.
如果该属性在事件对象中,您需要keyCode：
var keycode = "keyCode" in e ? e.keyCode : e.which;
这样,当事件对象中存在该属性时,以及当该属性也存在时,keyCode为零.
document.onkeydown = function(event) {
event = event || window.event;
var keyCode = "keyCode" in event ? event.keyCode : event.which;
switch (keyCode) {
case 37: console.log("37 was pressed", event); break;
case 39: console.log("39 was pressed", event); break;
}
};
编辑#1：其他评论者和答案是正确的.我忘了你不应该用按键事件检测控制键.改为onkeydown.
跨浏览器的完整HTML示例：
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>Key Codes Test</title>
</head>
<body>
<script type="text/javascript">
document.onkeydown = function(event) {
event = event || window.event;
var keyCode = "keyCode" in event ? event.keyCode : event.which;
switch (keyCode) {
case 37: console.log("37 was pressed", event); break;
case 39: console.log("39 was pressed", event); break;
}
};
</script>
<input type="text" size="30">
</body>
</html>