LeetCode OJ:Unique Binary Search Trees II

Unique Binary Search Trees II

 

Given n, generate all structurally unique BST‘s (binary search trees) that store values 1...n.

For example,
Given n = 3, your program should return all 5 unique BST‘s shown below.

   1         3     3      2      1
    \       /     /      / \           3     2     1      1   3      2
    /     /       \                    2     1         2                 3

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

算法思想:

DFS罗列所有可能情况:

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<TreeNode *>generate(int start,int end){
        vector<TreeNode *>result;
        if(start>end){
            result.push_back(NULL);
            return result;
        }
        for(int i=start;i<=end;i++){
            vector<TreeNode *>left=generate(start,i-1);
            vector<TreeNode *>right=generate(i+1,end);
            for(int j=0;j<left.size();j++)
                for(int k=0;k<right.size();k++){
                    TreeNode *root=new TreeNode(i);
                    root->left=left[j];
                    root->right=right[k];
                    result.push_back(root);
                }
        }
        return result;
    }
    vector<TreeNode *> generateTrees(int n) {
        return generate(1,n);
    }
};



LeetCode OJ:Unique Binary Search Trees II

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