# Demo：并行迭代 zip函数

names = ["anne","beth","george","damon","bob"]

ages = [12,45,32,102,101,103]

# names 与 ages 列表元素可以不等同，按数量少的进行对应

for name,age in zip(names,ages):

     print(name,"is",age,"years old!")

按索引迭代案例

按索引迭代方式一

strings = ["Alice","Bob","Nick"]

# strings[1] = "leo" #测试给列表添加元素后，的效果

# print(strings)

index = 0

for string in strings:

    if "ob" in string:

        strings[index] = "Tom" # 将含有“ob”的元素，替换为Tom

    index += 1

print(strings)

按索引迭代方式二

strings = ["Alice","Bob","Nick"]

index = 0

for index,string in enumerate(strings): 

    if "ob" in string:

        strings[index] = "Tom"

print(strings)