有四个数字:1、2、3、4,能组成多少个互不相同且无重复数字的三位数?各是多少?

def Permutation():
    list = []
    for i in range(1,5):
        for j in range(1,5):
            for s in range(1,5):
                #if i!=j&i!=s&j!=s:
                if i != j != s!=i:
                    t=i*100+j*10+s
                    if t in list:
                        pass
                    else:
                        list.append(t)
    return list
zz = Permutation()
print(zz)
输出:
[123, 124, 132, 134, 142, 143, 213, 214, 231, 234, 241, 243, 312, 314, 321, 324, 341, 342, 412, 413, 421, 423, 431, 432]

初学菜鸟,希望有大佬能指点不足,感激不尽!

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