在网上查到这样一个存储过程解密的方法,用起来简单,收藏到这里:
1 CREATE PROCEDURE sp_decrypt_sp (@objectName varchar(50)) 2 AS 3 ------------------------sql2000大于40000的----------------- 4 --原作:j9988 号:J老师 5 6 begin tran 7 begin 8 declare @objectname1 varchar(100) 9 declare @sql1 nvarchar(4000),@sql2 nvarchar(4000),@sql3 nvarchar(4000),@sql4 nvarchar(4000),@sql5 nvarchar(4000),@sql6 nvarchar(4000),@sql7 nvarchar(4000),@sql8 nvarchar(4000),@sql9 nvarchar(4000),@sql10 nvarchar(4000) 10 DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000) 11 declare @i int , @t bigint 12 declare @m int,@n int,@q int 13 set @m=(SELECT max(colid) FROM syscomments WHERE id = object_id(@objectName)) 14 set @n=1 15 --get encrypted data 16 create table #temp(colid int,ctext varbinary(8000)) 17 insert #temp SELECT colid,ctext FROM syscomments WHERE id = object_id(@objectName) 18 set @sql1=‘ALTER PROCEDURE ‘+ @objectName +‘ WITH ENCRYPTION AS ‘ 19 --set @sql1=‘ALTER PROCEDURE ‘+ @objectName +‘ WITH ENCRYPTION AS ‘ 20 set @q=len(@sql1) 21 set @sql1=@sql1+REPLICATE(‘-‘,4000-@q) 22 select @sql2=REPLICATE(‘-‘,4000),@sql3=REPLICATE(‘-‘,4000),@sql4=REPLICATE(‘-‘,4000),@sql5=REPLICATE(‘-‘,4000),@sql6=REPLICATE(‘-‘,4000),@sql7=REPLICATE(‘-‘,4000),@sql8=REPLICATE(‘-‘,4000),@sql9=REPLICATE(‘-‘,4000),@sql10=REPLICATE(‘-‘,4000) 23 exec(@sql1+@sql2+@sql3+@sql4+@sql5+@sql6+@sql7+@sql8+@sql9+@sql10) 24 while @n<=@m 25 begin 26 SET @OrigSpText1=(SELECT ctext FROM #temp WHERE colid=@n) 27 set @objectname1=@objectname+‘_t‘ 28 SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectName) and colid=@n) 29 if @n=1 30 begin 31 SET @OrigSpText2=‘CREATE PROCEDURE ‘+ @objectName +‘ WITH ENCRYPTION AS ‘-- 32 set @q=4000-len(@OrigSpText2) 33 set @OrigSpText2=@OrigSpText2+REPLICATE(‘-‘,@q) 34 end 35 else 36 begin 37 SET @OrigSpText2=REPLICATE(‘-‘, 4000) 38 end 39 --start counter 40 SET @i=1 41 --fill temporary variable 42 SET @resultsp = replicate(N‘A‘, (datalength(@OrigSpText1) / 2)) 43 44 --loop 45 WHILE @i<=datalength(@OrigSpText1)/2 46 BEGIN 47 --reverse encryption (XOR original+bogus+bogus encrypted) 48 SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^ 49 (UNICODE(substring(@OrigSpText2, @i, 1)) ^ 50 UNICODE(substring(@OrigSpText3, @i, 1))))) 51 SET @i=@i+1 52 END 53 --drop original SP 54 --EXECUTE (‘drop PROCEDURE ‘+ @objectName) 55 --remove encryption 56 --preserve case 57 SET @resultsp=REPLACE((@resultsp),‘WITH ENCRYPTION‘, ‘‘) 58 SET @resultsp=REPLACE((@resultsp),‘With Encryption‘, ‘‘) 59 SET @resultsp=REPLACE((@resultsp),‘with encryption‘, ‘‘) 60 IF CHARINDEX(‘WITH ENCRYPTION‘,UPPER(@resultsp) )>0 61 SET @resultsp=REPLACE(UPPER(@resultsp),‘WITH ENCRYPTION‘, ‘‘) 62 --replace Stored procedure without enryption 63 print @resultsp 64 --execute( @resultsp) 65 set @n=@n+1 66 end 67 drop table #temp 68 end 69 rollback tran 70 --适合40000字符。 71 --每次4000 print出来,自已贴。 72 --切记:我见过的解过程都是对原过程进行破坏。破解前一定要备份!!!! 73 --超过40000的,自已加SQL(我上面用SQL.SQL2--SQL10) 74 --超长的可加SQL11--sql20........ 75 76 77 GO