LeetCode #1996. The Number of Weak Characters in the Game
2023-11-20 12:13:16
The Number of Weak Characters in the Game
class Solution:
def numberOfWeakCharacters(self, properties: List[List[int]]) -> int:
"""
Time Complexity: O(n * log(n))
Space Complexity: O(1)
Where:
- n: size of properties.
"""
n = len(properties)
# Edge cases
if n < 2:
return 0
# Sort by (attack, defense) tuple in ASC order
properties.sort(key=lambda prop: (prop[0], prop[1]))
# Select the strongest pair for the remaining question space
max_prop = properties[-1]
ans = 0
next_max_prop = None
for idx in range(n - 2, -1, -1):
cur_prop = properties[idx]
if cur_prop[0] == max_prop[0]:
continue
if next_max_prop is None:
next_max_prop = cur_prop
# then we have: cur_prop[0] < max_prop[0]
if cur_prop[1] < max_prop[1]:
ans += 1
# Update the strongest pair for the remaining question space
if idx > 0 and properties[idx - 1][0] != cur_prop[0]:
if next_max_prop[1] > max_prop[1]:
max_prop = next_max_prop
next_max_prop = None
return ans